Answer:
The probability function of X and Y is

With k in {1,2,3,4,5,6}
Step-by-step explanation:
We can naturally assume that X and Y are independent. Because of that, P(X=a, Y=b) = P(X=a) * P(Y=b) for any a, b.
Note that, since the die is honest, then P(X=k) = 1/6 for any k in {1,2,3,4,5,6}. We can conclude as a consequence that P(X=k, Y=l) = P(Y=l)/6 for any k in {1,2,3,4,5,6}.
Y has a binomial distribution, with parameters n = 3, p = 1/2. Y has range {0,1,2,3}. Lets compute the probability mass function of Y:




Thus, we can conclude that the joint probability function is given by the following formula

For any k in {0,1,2,3,4,5,6}