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horsena [70]
3 years ago
13

A trough has ends shaped like isosceles triangles, with width 2 m and height 5 m, and the trough is 18 m long. Water is being pu

mped into the trough at a rate of 8 m3/min. At what rate (in m/min) does the height of the water change when the water is 2 m deep
Mathematics
1 answer:
fenix001 [56]3 years ago
8 0

9514 1404 393

Answer:

   5/9 m/min

Step-by-step explanation:

The depth of the water is 2/5 of the depth of the trough, so the width of the surface will be 2/5 of the width of the trough:

  2/5 × 2 m = 4/5 m

Then the surface area of the water is ...

  A = LW = (18 m)(4/5 m) = 14.4 m²

The rate of change of height multiplied by the area gives the rate of change of volume:

  8 m³/min = (14.4 m²)(h')

  h' = (8 m³/min)/(14.4 m²) = 5/9 m/min

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Which number produces a rational number when multiplied by 0.25?
Arlecino [84]
D is the correct answer.

0.25 is rational because it can be represented as a ratio of integers (1/4).

0.45 is rational because it can also be represented as a ratio of integers (9/20).

When you multiply rational numbers, you always end up with a rational number.

0.25*0.45=0.1125 or 1125/10000
4 0
3 years ago
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What is pi at its longest decimal?
victus00 [196]

Answer : Pi is infinite

If you want longest decimal that would take a very very long time use 3.14


Step-by-step explanation:


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3 years ago
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6 0
3 years ago
Select all nat apply.Which steps are involved in multiplying fractions?Multip, the denominators togetherMultiply the numerators
11Alexandr11 [23.1K]

We want to list the steps involved in multiplying fractions;

Taking an example;

\frac{2}{3}\times\frac{3}{4}

First steps are;

- Multiply the numerators together

- Multiply the Denominators together

\begin{gathered} =\frac{2\times3}{3\times4} \\ =\frac{6}{12} \end{gathered}

Next is to;

Check to see if the product can be simplified;

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So, we get the product to be;

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4 0
1 year ago
Oil leaked from a tank at a rate of r(t) liters per hour. the rate decreased as time passed, and values of the rate at two hour
Galina-37 [17]
The given data is
t, h:            0     2     4     6     8   10
r(t), L/h:   8.6  7.9  6.8  6.4  5.7  5.3

The lower and upper estimates for the total amount that leaked may be computed as the Left and Right Riemann sums.

The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
The plot of the graph is shown below.

The Left Riemann sum is
Sl = 2*(8.6+7.9+6.8+6.4+5.7) = 70.8 L

The Right Riemann sum is
Sr = 2*(7.9+6.8+6.4+5.7+5.3) = 64.2 L

Answer:
The lower estimate for oil leakage is 64.2 L
The upper estimate for oil leakage is 70.8 L

4 0
4 years ago
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