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horsena [70]
3 years ago
13

A trough has ends shaped like isosceles triangles, with width 2 m and height 5 m, and the trough is 18 m long. Water is being pu

mped into the trough at a rate of 8 m3/min. At what rate (in m/min) does the height of the water change when the water is 2 m deep
Mathematics
1 answer:
fenix001 [56]3 years ago
8 0

9514 1404 393

Answer:

   5/9 m/min

Step-by-step explanation:

The depth of the water is 2/5 of the depth of the trough, so the width of the surface will be 2/5 of the width of the trough:

  2/5 × 2 m = 4/5 m

Then the surface area of the water is ...

  A = LW = (18 m)(4/5 m) = 14.4 m²

The rate of change of height multiplied by the area gives the rate of change of volume:

  8 m³/min = (14.4 m²)(h')

  h' = (8 m³/min)/(14.4 m²) = 5/9 m/min

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Ivan

Sum of two monomials is not necessarily always a monomial.

For example:

Suppose we have two monomials as 2x and 5x.

Adding 2x+5x , we get 7x.

So if two monomials are both like terms then their sum will be a monomial.

Suppose we have two monomials as 3y and 4x

Now these are both monomials but unlike, so we cannot add them together and sum would be 3y + 4x , which is a binomial.

So if we have like terms then the sum is monomial but if we have unlike terms sum is binomial.

Product of monomials:

suppose we have 2x and 5y,

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4 0
3 years ago
Read 2 more answers
Please help due soon!!!
butalik [34]

Hey there!


Question #1.
2^6 + (2^3)^3

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= 64 + 8^3

= 64 + 512

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Therefore, the answer should be:

Option A. 576


Question #2.
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= 14,641

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Therefore, the answer should be:

Option C. 11^4


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

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Answer:

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