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nirvana33 [79]
3 years ago
13

What is the center of a stem and leaf plot

Mathematics
2 answers:
borishaifa [10]3 years ago
7 0
A stem and leaf plot, or stem plot, is a technique used to classify either discrete or continuous variables. A stem and leaf plot is used to organize data as they are collected. A stem and leaf plot looks something like a bar graph. Each number in the data is broken down into a stem and a leaf, thus the name.
maksim [4K]3 years ago
3 0

Answer:

Step-by-step explanation:

You might be interested in
Question
Kay [80]

Answer:

f(x)=2(x-2)(x^2+64)

Step-by-step explanation:

A standard polynomial in factored form is given by:

f(x)=a(x-p)(x-q)...

Where <em>p</em> and <em>q</em> are the zeros.

We want to find a third-degree polynomial with zeros <em>x</em> = 2 and <em>x </em>= -8i and equals 320 when <em>x </em>= 4.

First, by the Complex Root Theorem, if <em>x</em> = -8i is a root, then <em>x </em>= 8i must also be a root.

Therefore, we acquire:

f(x)=a(x-(2))(x-(-8i))(x-(8i))

Simplify:

f(x)=a(x-2)(x+8i)(x-8i)

Expand the second and third factors:

=(x+8i)x+(x+8i)(-8i)\\\\=(x^2+8ix)+(-8ix-64i^2)\\\\=(x^2)+(8ix-8ix)+(-64i^2)\\\\=x^2-64(-1)\\\\ =x^2+64

Hence, our function is now:

f(x)=a(x-2)(x^2+64)

It equals 320 when <em>x</em> = 4. Therefore:

320=a(4-2)(4^2+64)

Solve for <em>a</em>. Evaluate:

320=(2)(80)a

So:

320=160a\Rightarrow a=2

Our third-degree polynomial equation is:

f(x)=2(x-2)(x^2+64)

7 0
3 years ago
Use the zero property product to find the solutions to the equation x^2-9= 16
Luba_88 [7]
Subtract 16 to get
  x^2 -25 = 0
Factor this as
  (x -5)(x +5) = 0

The zero product property tells you the product will be zero when one of the factors is zero.

For x-5 = 0
  x = 5

For x+5 = 0
  x = -5

The appropriate choice is
  3) x=-5 or x=5
4 0
3 years ago
Who can help me with this question?​
a_sh-v [17]

\large\mathcal{\red{ \implies \:  2 \: \pi \:  {r}^{2}  \:  +  \: 2 \: \pi \: r \: h}}

Option ( C ) is the correct answer.

6 0
3 years ago
Read 2 more answers
Kim purchased white vases, red vases, and flowers to create centerpieces for an event. The flowers cost a total of $336 and each
laiz [17]

Option A:

I and III only the answers.

Solution:

Let white vases be "w" and red vases be "r".

Cost of total flower = $336

Cost of each vase = $11

Total cost of the centerpieces

                = Cost of (white vases + red vases)  + Cost of flowers

                = 11(w + r) + 336

                = 11w + 11r + 336

Total cost of the centerpieces = 11w + 11r + 336 = 11(w + r) + 336

Therefore I and III only the answers.

Option A is the correct answer.

4 0
3 years ago
How much of a 50% Alcohol solution should we mix with 10 gallons of 35% solution to get 40% solution
Marianna [84]
<h3>5 gallons of 50 % alcohol solution is used</h3>

<em><u>Solution:</u></em>

Let "x" is the gallons of 50 % alcohol solution

Then, 10 gallons is 35 % solution

The, 10 + x is the gallons of 40 % solution

Then, according to question,

"x" gallons of 50 % solution is mixed with 10 gallons of 35 % solution to get 10 + x gallons of 40 % solution

Therefore,

50 \% \times x + 35 \% \times 10 = 40 \% \times (10+x)\\\\\frac{50}{100} \times x + \frac{35}{100} \times 10 = \frac{40}{100} \times 10+x\\\\0.5x + 3.5 = 0.4(10+x)\\\\0.5x + 3.5=4+0.4x\\\\0.5x-0.4x = 4-3.5\\\\0.1x = 0.5\\\\Divide\ both\ sides\ by\ 0.1\\\\x = 5

Thus 5 gallons of 50 % alcohol solution is used

3 0
3 years ago
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