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Setler [38]
3 years ago
6

José vende dos bicicletas, cada una a 198 soles. Si en una ganó el 10% y en la otra perdió el 10%. ¿Cuanto ganó o perdió pir la

venta de las dos bicicletas?
Mathematics
1 answer:
Arte-miy333 [17]3 years ago
3 0

Answer:

I win 10% = 217.8

I lost 10% = 178.2

217.8 + 178.2 = 396

198 + 198 = 396

396 = 396

I neither gain nor lose anything: V

Step-by-step explanation:

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Pani-rosa [81]
(a) y = 2x + 3
(b) (1,5), (3,3); y = 3x + 3      5 = m1 + b, 3 = m3 + b
(c) coincident i believe, because it is not independent or inconsistent
(d) 2x + 3 = 3x + 3
     (-2x)(-3)  (-2x)(- 3)
0 = -2x
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hope this helps
5 0
3 years ago
Read 2 more answers
I need to find the surface area and volume of all three figures. If you could provide what equations you used to I will be grate
Margarita [4]

Answer:

Part 1) <em>Sphere</em> The surface area is equal to SA=196\pi\ m^{2} and the volume is equal to V=\frac{1,372}{3}\pi\ m^{3}

Part 2) <em>Cone</em> The surface area is equal to SA=(16+4\sqrt{65})\pi\ units^{2} and the volume is equal to V=\frac{112}{3}\pi\ units^{3}

Part 3) <em>Triangular Prism</em> The surface area is equal to SA=51.57\ mm^{2} and the volume is equal to V=17.388\ mm^{3}

Step-by-step explanation:

Part 1) The figure is a sphere

a) Find the surface area

The surface area of the sphere is equal to

SA=4\pi r^{2}

we have

r=14/2=7\ m ----> the radius is half the diameter

substitute

SA=4\pi (7)^{2}

SA=196\pi\ m^{2}

b) Find the volume

The volume of the sphere is equal to

V=\frac{4}{3}\pi r^{3}

we have

r=14/2=7\ m ----> the radius is half the diameter

substitute

V=\frac{4}{3}\pi (7)^{3}

V=\frac{1,372}{3}\pi\ m^{3}

Part 2) The figure is a cone

a) Find the surface area

The surface area of a cone is equal to

SA=\pi r^{2} +\pi rl

we have

r=4\ units

h=7\ units

Applying Pythagoras Theorem find the value of l (slant height)

l^{2}=r^{2} +h^{2}

substitute the values

l^{2}=4^{2} +7^{2}

l^{2}=65

l=\sqrt{65}\ units

so

SA=\pi (4)^{2} +\pi (4)(\sqrt{65})

SA=16\pi +4\sqrt{65}\pi

SA=(16+4\sqrt{65})\pi\ units^{2}

b) Find the volume

The volume of a cone is equal to

V=\frac{1}{3}\pi r^{2}h

we have

r=4\ units

h=7\ units

substitute

V=\frac{1}{3}\pi (4)^{2}(7)

V=\frac{112}{3}\pi\ units^{3}

Part 3) The figure is a triangular prism

a) The surface area of the triangular prism is equal to

SA=2B+PL

where

B is the area of the triangular base

P is the perimeter of the triangular base

L is the length of the prism

<em>Find the area of the base B</em>

B=\frac{1}{2} (2.7)(2.3)=3.105\ mm^{2}

<em>Find the perimeter of the base P</em>

P=2.7*3=8.1\ mm

we have

L=5.6\ mm

substitute the values

SA=2(3.105)+(8.1)(5.6)=51.57\ mm^{2}

b) Find the volume

The volume of the triangular prism is equal to

V=BL

where

B is the area of the triangular base

L is the length of the prism

we have

B=3.105\ mm^{2}

L=5.6\ mm

substitute

V=(3.105)(5.6)=17.388\ mm^{3}

5 0
3 years ago
Please help!!!!!!!!!!!!!!
Vlad1618 [11]
What do you need specifically just that one question
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3 years ago
1) (19,-16).(-7, -15)
murzikaleks [220]

Answer:

hello child be good

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Step-by-step explanation:

4 0
3 years ago
If mRST = 65, mQST = 2x, and mQSR = 3x – 10, what is the value of x?
astraxan [27]
 The answer is B because <span>(2*15)+(3*15-10)= 65</span>
6 0
3 years ago
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