Answer:
There are a total of 2011 integer divisors.
Step-by-step explanation:
The only primes p such that 1/p has finite spaces after the coma are 2 and 5. If we divide a number with last digit odd we will obtain 1 extra digit after the decimal point and if we divide a number by 5 we will obtain 1 more digit if that number has a last digit in the decimal which is not a multiple of 5.
If we take powers of those primes we will obtian one more digit each time. In order to obtain more digits it is convinient to divide by a power of 2 instead of a power of 5, because the resulting number will be smaller.
If we want 2010 digits after the decimal point, we need to divide 1 by 2 a total of 2010 times, hence f(2010) = 2²⁰¹⁰, which has as positive integer divisors every power of 2 between 0 and 2010, hence there are a total of 2011 integer divisors of f(2010).
It is 2 .............................
Answer:
See below ~
Step-by-step explanation:
<u>Question #8</u>
- Area = 10 x 11.7
- Area = <u>117 m²</u>
<u></u>
<u>Question #10</u>
- Area = 11 x 11
- Area = <u>121 m²</u>
Answer:
7 but im not sure
Step-by-step explanation:
