Answer:
t= -1
Step-by-step explanation:

where (x₁, y₁) is the first coordinate and (x₂, y₂) is the second coordinate



cross multiply:
1(t -6)= 7(-1)
t -6= -7
+6 on both sides:
t= -7 +6
t= -1
Answer:
see explanation
Step-by-step explanation:
Complementary angles sum to 90°, thus
∠A ∠B = 90 ← substitute values
5x - 27 + 4x - 27 = 90, that is
9x - 54 = 90 ( add 54 to both sides )
9x = 144 ( divide both sides by 9 )
x = 16
Hence
∠A = 5x - 27 = (5 × 16) - 27 = 80 - 27 = 53°
∠B = 4x - 27 = (4 × 16) - 27 = 64 - 27 = 37°
9514 1404 393
Answer:
39.375 : 65.625
Step-by-step explanation:
The meaning of "reduce" in this context is unclear. We assume you want to divide the quantity 105 into parts that have a ratio of 3 : 5. Then the smaller part will be 3/(3+5) = 3/8 of the total; the larger part will be 5/8 of the total.
3/8 × 105 = 39 3/8
5/8 × 105 = 65 5/8
The divided quantities are ...
39.375 : 65.625
Answer:
t(s) is in rejection zone then we reject H₀.
Bad weather indeed make apples weight decrease
Step-by-step explanation:
Normal Distribution
population mean μ₀ = 9.5 ou
sample size = n = 16 then we should apply t-student table
degree of fredom df = n - 1 df = 16 - 1 df = 15
1.-Test hypothesis
H₀ null hypothesis μ₀ = 9.5
Hₐ alternative hypothesis μ₀ < 9.5
One left tail-test
2.-Confidence level 95 %
α = 0,05 and df = 15 from t-student table we get t(c) = - 1.761
3.-Compute t(s)
t(s) = [ μ - μ₀ ] /√s/n t(s) = (9.32 - 9.5 )* √16 / 0.18
t(s) = - 0.18*√16 / 0.18
t(s) = - 4
4.-Compare t(s) and t(c)
t(s) < t(c) -4 < - 1.761
Then t(s) is in the rejection zone.
5.- Decision
t(s) is in rejection zone then we reject H₀.
Farmer conclude that bad weather make apples weight decrease
We have that
case <span>A)
(x – 2)(x + 2)(x</span>²<span> + 8)(x4 + 8)
(x</span>²-4)(x² + 8)(x4 + 8)
case <span>B)
(x – 2)(x – 2)(x</span>²<span> + 4)(x4 + 16)
(x-2)</span>²(x² + 4)(x4 + 16)
case <span>C)
(x – 2)(x + 2)(x</span>²<span> + 4)(x4 + 16)
(x</span>²-4)(x² + 4)(x4 + 16)
(x4 -16)(x4 + 16)
(x8-256)
case <span>D)
(x + 2)(x + 2)(x</span>²<span> + 4)(x4 + 16)
(x+2)</span>²(x² + 4)(x4 + 16)
the answer is
the option
<span>C) (x – 2)(x + 2)(x2 + 4)(x4 + 16) </span>