Answer:
Correct choice is D
Step-by-step explanation:
Consider right triangle PTE (Patty, Todd, Emma). In thistriangle PT=50 mi - the distanse between Patty and Todd, the distance between Patty and Emma PE and the distance between Emma and Todd ET are unknown. The angle PET has the measure of 40°. Then
<h3>
Answer: Tony is correct</h3>
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Explanation:
There are number of ways to go about this, but let's pick on the sides marked in the diagram below (circled in red and blue). I picked on those sides specifically because they are on either side of the marked angles (A and Q).
They help form the proportion below, in which we'll show later on its a false statement.
AE/PQ = AB/QR
24/(14.5) = 18/(11.5)
24*11.5 = 14.5*18
270 = 261
We arrive at a false statement at the end, so the original proportion is false. Furthermore, it means the figures are <u>not</u> similar.
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We could try the other way around and try to see if
AE/QR = AB/PQ
is true or not
Let's find out
24/(11.5) = 18/(14.5)
24*14.5 = 11.5*18
348 = 207
We see this is false as well. The gap is even bigger than before, so the first scenario was slightly close to having similar polygons. But neither case works perfectly. So that's why we don't have similar polygons and why Tony is correct. It's not enough to look at the angles only when dealing with polygons that have more than 3 sides. If we were just focused on triangles, then Jacenta would be correct.
Answer:
x=7
Step-by-step explanation:
∠STP=∠SWT+∠TSW(exterrior ∠ of Δ)
15x=7x+1+7x+6
x=7
Answer:
261.7
Step-by-step explanation:
Z = 1.555 should be used
If we seek an 88% confidence interval, that means we only want a 12% chance that our interval does not contain the true value.
Assuming a two-sided test, that means we want a 6% chance attributed to each tail of the Z-distribution.
the zα/2 value of z0.06.
This z value at α/2=0.06 is the coordinate of the Z-curve that has 6% of the distribution's area to its right, and thus 94% of the area to its left. We find this z-value by reverse-lookup in a z-table.
<h3>What is Z-distribution?</h3>
The standard normal distribution, also called the z-distribution, is a special normal distribution where the mean is 0 and the standard deviation is 1.
Any normal distribution can be standardized by converting its values into z-scores. Z-scores tell you how many standard deviations from the mean each value lies.
<h3>Why is z-score used?</h3>
The standard score (more commonly referred to as a z-score) is a very useful statistic because it
(a) allows us to calculate the probability of a score occurring within our normal distribution and
(b) enables us to compare two scores that are from different normal distributions.
To learn more about Z-distribution from the given link
brainly.com/question/17039068
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