She needs to make sure the camera is on and working, if she doesn't than it wont tranfer
<span>The answer is RAM. Chat messages are most likely to be found in the RAM of the computer. It is Random Access Memory. </span><span>RAM is considered volatile memory, which means that the stored information is lost when there is no more power.</span>
Answer:
#include <stdio.h>
#include <ctype.h>
void printHistogram(int counters[]) {
int largest = 0;
int row,i;
for (i = 0; i < 26; i++) {
if (counters[i] > largest) {
largest = counters[i];
}
}
for (row = largest; row > 0; row--) {
for (i = 0; i < 26; i++) {
if (counters[i] >= row) {
putchar(254);
}
else {
putchar(32);
}
putchar(32);
}
putchar('\n');
}
for (i = 0; i < 26; i++) {
putchar('a' + i);
putchar(32);
}
}
int main() {
int counters[26] = { 0 };
int i;
char c;
FILE* f;
fopen_s(&f, "story.txt", "r");
while (!feof(f)) {
c = tolower(fgetc(f));
if (c >= 'a' && c <= 'z') {
counters[c-'a']++;
}
}
for (i = 0; i < 26; i++) {
printf("%c was used %d times.\n", 'a'+i, counters[i]);
}
printf("\nHere is a histogram:\n");
printHistogram(counters);
}
Answer:
evaluation of decision effectiveness
Explanation:
Based on the information provided within the question it can be said that in this scenario she is in the stage of evaluation of decision effectiveness. This is the stage after the decision has been made in which the individual begins to analyze the decision and determine whether the decision was as effective as originally anticipated , and whether or not it was the correct decision.
Answer:
The answer is "2".
Explanation:
In the given question some information is missing, that is "The propagation time for satellite to earth" which is "270 milliseconds" so, the description to this question can be defined as follows:
Given values:
Bandwidth = 64 kbps
Data frames = 512 bytes
Propagation Time (tp ) =270 ms
Change Bandwidth kbps to bps:
1 kb= 1024 bytes
calculated bandwidth= 64 kbps = 64×1024 bps = 65536 bps
1 bytes = 8 bits
512 bytes = 512 × 8 = 4096 bits
Frame length = 4096 bits
Formula
Transmission time (Tt) = Frame length /Bandwidth
Window size = 1+2a
where a = Propagation time/Transmission time
Calculate Transmission time:
Transmission time (Tt) = 4096 / 65536
Transmission time (Tt)= 625 m.sec
Calculate Window size:
Window size = 1+2(270/625)
Window size
= 1+2(0.432)
Window size
= 1+0.864
Window size = 1.864
Window size
= 2
