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4 years ago

6

1.3.4 Practice: Modeling: Multiplying Binomials What are the answers to the work sheet?

1 answer:

Pie4 years ago

8 0

The name of the book that you use.

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Evaluate the following expression using the values given: Find x3 − 2y2 − 3x3 z4 if x = 3, y = 5, and z = −3.

eduard

The Answer is -398

3^3 - 2(5)^2 - (5)^3
27-2(5)^2-3(5)^3
27-2(25)-3(5)^3
27-2(25)-3(125)
27-50-375
-398

3 0

3 years ago

Which of the following is not an inertial reference frame? Which of the following is not an inertial reference frame?

hammer [34]

An inertial reference frame is a frame of reference in which a body remains at rest OR moves with a constant LINEAR velocity. Answer choices A, C, and D are moving linearly at a constant rate and are all inertial frames of reference. Answer choice E is motionless, and is therefor an inertial frame of reference. Answer choice B is rotating at a constant rate. Rotation is not an inertial frame of reference.
Therefor, the answer is B.

7 0

3 years ago

What is the equation of the vertical line through (2,3)?

VARVARA [1.3K]

Answer:

The answer is X=2.

Step-by-step explanation:

6 0

3 years ago

2<br> 5<br> Explain the "T" and "mering role making

Naddik [55]

Show me the question please

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3 years ago

What is the correct first step to solve this system of equations by elimination?

storchak [24]

$\bold{\huge{\pink{\underline{ Solution }}}}$

$\bold{\underline{ Given }}$

<u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

$\bold{\underline{ To \: Find }}$

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>

$\bold{\underline{ Let's \: Begin }}$

$\sf{ 2x - 3y = -6 ...eq(1)}$

$\sf{ x + 3y = 12 ...eq(2)}$

<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>

$\sf{ 2( x + 3y = 12 )}$

$\sf{ 2x + 6y = 24 }$

<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{ 2x + 6y -( 2x - 3y) = 24 -(-6)}$

$\sf{ 2x + 6y - 2x + 3y = 24 + 6 }$

$\sf{ 9y = 30 }$

$\sf{ y = 30/9}$

$\sf{\red{ y = 10/3}}$

<u>Now</u><u>, </u><u> </u><u>Subsitute</u><u> </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

$\sf{ 2x - 3(10/3) = -6 }$

$\sf{ 2x - 10 = -6 }$

$\sf{ 2x = -6 + 10}$

$\sf{ x = 4/2}$

$\sf{\red{ x = 2}}$

Hence, The value of x and y is 2 and 10/3

6 0

3 years ago