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Marizza181 [45]

3 years ago

13

Jim’s football team started a play on the 50 yard line. On the first play, the team had a 7-yard gain. On the second play, they

lost 10 yards. What yard line was the ball on at the end of the second play?

1 answer:

Advocard [28]3 years ago

3 0

Answer:

47 yard line

Step-by-step explanation:

50+7-10=47

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Callie is comparing the costs of two options for her college education.

Ainat [17]

Answer:

Callie's comparison of two options for college education

The true statement is:

She would save $11,300 by choosing option A.

Step-by-step explanation:

Cost Analyses:

Option A: Community College + University Total Expenses

Tuition & Fees $5,800 ($2,900 x 2) + $19,000 ($9,500 x 2) = $24,800

Scholarships ($1,600) ($800 x 2) + ($20,000) ($10,000 x 2)=($21,600)

Room & Board $2,500 ($1,250 x 2) + $23,000 ($11,500 x 2) = $25,500

Work-Study + ($4,000) ($2,000 x 2) = ($4,000)

Total Cost $6,700 + $18,000 = $24,700

Option B: 4 years' University

Tuition & Fees $38,000 ($9,500 x 4)

Scholarships ($40,000) ($10,000 x 4)

Room & Board $46,000 ($11,500 x 4)

Work-Study ($8,000) ($2,000 x 4)

Total Cost $36,000

Difference between the two options = $11,300 ($36,000 - $24,700

5 0

4 years ago

Read 2 more answers

one number is 4 less than 3 times another number. if their sum is 16, find the numbers. which of the following equations could b

Olin [163]

X=3y-4
x+y=16

3y-4+y=16

4y = 20

y =5

x+y=16

x+5=16

x=16-5

x=11
y=5

hope helped

5 0

3 years ago

Nana76 [90]

Answer:

$365.37

Step-by-step explanation:

add the hours up which is 20+19.5=39.5

then multiply by the wage 9.25 which is 39.5*9.25 which equals 365.375 and you cant round a penny up because its not possible in real life so your answer is just 365.37

8 0

2 years ago

Ayudemen porfavor . Determine 4 ala potencia x + 4 ala potencia -x, si se sabe que 2ala potencia x + 2 ala potencia -x =3

Afina-wow [57]

Answer:

Es igual a 7.

Step-by-step explanation:

Ok, sabemos que:

$2^x + 2^{-x} = 3$

Queremos calcular:

$4^x + 4^{-x}$

Tambien sabemos que 4 = 2*2

Entonces:

$4^x + 4^{-x} = (2*2)^x + (2*2)^{-x}$

y sabemos que 2*2 = 2^2

Entonces:

$4^x + 4^{-x} = (2*2)^x + (2*2)^{-x} = (2^2)^x + (2^2)^{-x}$

y ahora podemos usar la relación:

$(a^n)^m = (a^m)^n = a^{m*n}$

entonces:

$(2^2)^x + (2^2)^{-x} = (2^x)^2 + (2^{-x})^2$

Ahora podemos completar cuadrados sumando y restando el termino:

$2*(2^x)*(2^{-x})$

Asi tendremos:

$(2^x)^2 + (2^{-x})^2 = (2^x)^2 + (2^{-x})^2 + 2*(2^x)*(2^{-x}) - 2*(2^x)*(2^{-x}) = (2^x + 2^{-x})^2 - 2*(2^x)*(2^{-x})$

Entonces de momento tenemos que:

$4^x + 4^{-x} = (2^x + 2^{-x})^2 - 2*(2^x)*(2^{-x})$

Sabemos que el termino que esta dentro del parentesis es igual a 3.

Y tambien podemos usar la propiedad:

$a^n*a^m = a^{n + m}$

en el termino de la derecha.

Asi tendremos:

$(2^x + 2^{-x})^2 - 2*(2^x)*(2^{-x}) = (3)^2 - 2*2^{x + (-x)} = 9 - 2 = 7$

7 0

3 years ago

Answer this please! The question and answers options are on the picture!

Makovka662 [10]

Answer:

WHAT PICTURE

Step-by-step explanation:

7 0

3 years ago