The gallons of the first brand of antifreeze should be 60 gallons.
The gallons of the second brand of antifreeze should be 90 gallons.
<h3>What are the linear equations that represent the question?</h3>
0.2f + 0.45s = 52.50 (0.35 x 150) equation 1
f + s = 150 equation 2
Where:
- f = gallons of the first antifreeze
- s = gallons of the second antifreeze
how many gallons of each brand of antifreeze must be used?
Multiply equation 2 by 0.2
0.2f + 0.2s = 30 equation 3
Subtract equation 3 from equation 2
0.25s = 22.50
s = 22.50 / 0.25
s = 90
f = 150 - 90 = 60 gallons
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Answer:
The answers are in the attachment
Translate to english and i’ll help
Answer: 0.87400mg of caffeine.
Step-by-step explanation:
You have
N(t)=N0(e^−rt)(1)
as a general Exponential decay equation where N0 is the amount at t=0, N(t) is the amount remaining at time t and r is the exponential decay constant. You're specifically given that after 10 hours, the decay factor is 0.2601, i.e.,
N(10)/N(0)=N0(e^−10r)/N0(e^0)= e^−10r=0.2601 . .(2)
Taking the last 2 parts of (2) to the power of 0.1t gives
e^−rt=0.2601^.1t . .(3)
This means that
N(t)=N0(e^−rt)=N0(0.2601^.1t). .(4)
Also,
N(2.56)N(1.56)=N0(0.2601.1(2.56))N0(0.2601.1(1.56))=0.2601.1(2.56−1.56)=0.2601^.1
= 0.87400mg of caffeine.
