Answer:
you want 4 correct and 16 incorrect
there are 20 questions
each question has four answers, so
P(right answer) = 1/4
P(wrong answer) = 3/4
----
Since you want 4 correct of 20 we have a combination of 20C4
This is a binomial problem where p = 1/4, q = 3/4 and we get
(20 "choose" 4)*(probability correct)^(number correct)*(probability incorrect)^(number incorrect)
putting numbers in we get
(20c4)*(1/4)^4*(3/4)^16
This gives us
~ .189685
Step-by-step explanation:
Answer:
b c & e
Step-by-step explanation:
trust me
Remember
a(b+c)=ab+ac
and you can do ANYTTHING to be
L=5B
divide both sides by 5
L/5=B
sub L/5 for B in other equation
L+7=3((L/5)+7)
distribute
L+7=(3L)/5+21
minus 7 both sides
L=(3L)/5+14
time boths sides by 5
5L=3L+70
minus 3L both sides
2L=70
divide 2
L=35
Answer:
300
Step-by-step explanation:
each ten is worth 10 so 10x30+ 300
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