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vaieri [72.5K]
3 years ago
8

The state highway department is studying traffic patterns on one of the busiest highways in the state. As part of the study, the

department needs to estimate the average number of vehicles that pass an intersection each day. A random sample of 64 days gives us a sample mean of 14,205 cars and a sample standard deviation of 1,010 cars. What is the 92% confidence interval estimate of μ, the mean number of cars passing the intersection?
Mathematics
1 answer:
Nesterboy [21]3 years ago
4 0

Answer:

jfdslkhfbdjskbvdslkjfbv;kjdabva;ksjdvbljfslfdhglkdufhgdsrlkgujdsgljkdsfbvlkfdjdd;hgs;dihg;dsifvsj

Step-by-step explanation:

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A nutrition laboratory tested 25 "reduced sodium" hotdogs of a certain brand, finding that the mean sodium content is 310 mg wit
inessss [21]

Answer:

The  95% confidence interval is  295.9 < \mu< 324.1

A   95% level of confidence mean that there is 95%  chance  that the true population mean will be in this interval

Step-by-step explanation:

From the question we are told that

    The sample size is  n  =  25

    The mean is  \= x  =  310 \ mg

     The standard deviation is  \sigma =  36 \ mg

Given that the confidence level is  95% then the level of significance is mathematically represented as

           \alpha  =  100 - 95

=>        \alpha  =  5\%

=>        \alpha  =  0.05

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table , the value is  

           Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }  =  1.96

Generally the margin of error is mathematically represented as

        E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

substituting values

        E =  1.96 *  \frac{36 }{\sqrt{25} }

        E = 14.1

The 95% level of confidence interval  is mathematically represented as

      \= x - E < \mu

substituting values

     310- 14.1 < \mu< 310+ 14.1

     295.9 < \mu< 324.1

The  95% level of confidence mean that there is 95%  chance  that the true population mean will be in this interval

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3 years ago
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