10g^3 - 8g^2 + 5g - 14 + 10g^2 + 12g
its just a matter of combining like terms
10g^3 + 2g^2 + 17g - 14
The answer : 20%
Hope it help u
Answer:
f^-1(x) = (x -14)/10
Step-by-step explanation:
You can find the inverse function by solving for y:
x = f(y)
Here, that is ...
x = 10y +14 . . . . . use the definition of f(y)
x -14 = 10y . . . . . . subtract 14
(x -14)/10 = y . . . . divide by the coefficient of y
So, your inverse function is ...
f^-1(x) = (x -14)/10
(y_final-y_start)/(x_final-x_start) always! :) that easy
(-6-2)/(2-0) = -4
You probably know that if the interval was pretty small, between 0 and 0.0001, it would take you to the concept of slope and derivatives, but average change is just ignoring anything in between x=0, and x=2 (it could go up/down million times, and still the answer would be -4)
hope it helps
