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3 years ago

Which of the following expressions would represent a class of 56 students divided equally into 8 groups

Mathematics

1 answer:

I am Lyosha [343]3 years ago

4 0

<h3>7 students in one group </h3><h3>may it's helpful</h3>

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I need the answer quick before my timer goes out

max2010maxim [7]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Anyone please???????

leva [86]

Answer:

$\boxed{\sf B)\: x=\sqrt{17}}$

Step-by-step explanation:

<u>Use the Pythagorean Theorem</u>

The equation for the Pythagorean Theorem is $\tt a^2+b^2=c^2$

* a and b are the lengths of the legs, and c is the hypotenuse.*

(To know which side is the hypotenuse look at longest side which is across the right angle).

a= x, b=8, c=9

$\sf a^2+b^2=c^2$

Let's Plug in the side lengths:

$\sf x^2+8^2=9^2$

Evaluate 8^2 and 9^2:

$\sf x^2+64=81$

Subtract 64 from both sides:

$\sf x^2+64-64=81-64$

$\sf x^2=17$

Take the square root of both sides:

$\sf x=\sqrt{17}$

___________________________

5 0

2 years ago

Read 2 more answers

Which numerical expression is equivalent to 6 to the power of 3 times 4 to the power of 2

tangare [24]

Answer:

6^3 * 4^2

Step-by-step explanation:

6 0

3 years ago

A basketball player shoots a basketball that reaches a height above 15 feet before landing back on the ground exactly after 7 se

Papessa [141]

Answer:

I and IV

Step-by-step explanation:

Since the height of the basketball reaches above 15 feet, hence the maximum of the function should be greater than 15 feet. Also at 7 seconds, the ball is on the ground, hence f(7) = 0 feet

The maximum of a function is at x = -b/2a

i) f(x) = -(x-3)² + 16 = -(x² - 6x + 9) + 16 = -x² + 6x + 7

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3-3)² + 16 = 16 > 15

Also f(7) = - (7 - 3)² + 16 = 0

Hence this option is correct

ii) f(x) = -x² + 8x - 7

The maximum of a function is at x = -b/2a = -8 / 2(-1) = 4

f(4) = -4² + 8(4) - 7 = 9 < 15 not correct

Also f(7) = - 7² + 8(7) - 7 = 0

Hence this option is not correct since the maximum f(4) = 9 < 15

iii) f(x) = -(x-3)² + 14 = -(x² - 6x + 9) + 14 = -x² + 6x + 5

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3-3)² + 14 = 14 < 15

Also f(7) = - (7 - 3)² + 14 = -2

Hence this option is not correct since the maximum f(4) = 9 < 15 and f(7) ≠ 0

iv)f(x) = -x² + 6x + 7

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3)² + 6(3) + 7 = 16 > 15

Also f(7) = - (7)² + 6(7) + 7 = 0

Hence this option is correct

3 0

3 years ago

35,520 divided by 96

Vlada [557]

The answer would be 370

3 0

2 years ago