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3 years ago

Evaluate 3x2 - 4 when x = 2. A. 12 B. 32 c. 2 D. 8

Mathematics

2 answers:

Svetach [21]3 years ago

5 0

$\text{Plug in and solve:}\\\\3(2)^2-4\\\\3(4)-4\\\\12-4\\\\8\\\\\boxed{\text{D). 8}}$

Bumek [7]3 years ago

3 0

Answer:

Step-by-step explanation:

3x^2 - 4

Let x = 2

3 * 2^2 -4

Exponents first

3 *4 -4

Then multiply

12 -4

Now subtract

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Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random

Katen [24]

Answer:

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

Step-by-step explanation:

Given

$n = 200$

$x_1 = 34$ -- City C

$x_2 = 54$ --- City K

Required

Determine the 90% confidence interval

This is calculated using:

$CI = \bar x \± z\frac{\sigma}{\sqrt n}$

Calculating $\bar x$

$\bar x = \bar x_1 - \bar x_2$

$\bar x = \frac{x_1}{n} - \frac{x_2}{n}$

$\bar x = \frac{34}{200} - \frac{54}{200}$

$\bar x = 0.17 - 0.27$

For a 90% confidence level, the z-score is 1.65. So:

$z = 1.65$

Calculating the standard deviation $\sigma$

$\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }$

So:

$\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }$

$\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}$

So:

$CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}$

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

7 0

2 years ago

Graph the function y=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20-2-5" id="TexFormula1" title="\sqrt{x} -2-5" alt="\sqrt{

Rashid [163]

Answer:

(3, -4)

Step-by-step explanation:

The correct equation is:

$y=\sqrt{x-2}-5$

From the list of given points, we have to identify which point lies on the graph. This can be done by using the value of x-coordinates from the given points and see if they result in the corresponding y-coordinate:

For point (1, 4)

$y=\sqrt{1-2}-5=\sqrt{-1}-5$ , This is not equal to 4, so it does not lie on the graph of given function.

For point (3, -4)

$y=\sqrt{3-2}-5=\sqrt{1}-5=-4$ , The answer ans corresponding y-coordinate are the same. This means, (3, -4) point lies on the graph of given function.