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fiasKO [112]
2 years ago
13

Write the following quadratic in standard form. Then identify a, b, and c. y² - 7y + 6 = -6

Mathematics
1 answer:
Charra [1.4K]2 years ago
7 0

Answer:

Therefore,

y^{2}-7y+12=0       ....Standard form.

a=1\\b=-7\\c=12    ......Numerical Coefficients.

Step-by-step explanation:

Given:

y^{2}-7y+6=-6

To Find:

a ,b , c

Solution:

Quadratic:

A quadratic equation is an equation of the second degree.

Meaning it contains at least one term that is squared.

The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

Here it is given as

y^{2}-7y+6=-6

Adding 6 on both the side we get

y^{2}-7y+6+6=-6+6

y^{2}-7y+12=0

Which is Quadratic Equation in STANDARD form Where,

a=1\\b=-7\\c=12

Therefore,

y^{2}-7y+12=0       ....Standard form.

a=1\\b=-7\\c=12    ......Numerical Coefficients.

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