Question

Write the following quadratic in standard form. Then identify a, b, and c. y² - 7y + 6 = -6

Answer 1

Answer:

Therefore,

$y^{2}-7y+12=0$       ....Standard form.

$a=1\\b=-7\\c=12$    ......Numerical Coefficients.

Step-by-step explanation:

Given:

$y^{2}-7y+6=-6$

To Find:

a ,b , c

Solution:

Quadratic:

A quadratic equation is an equation of the second degree.

Meaning it contains at least one term that is squared.

The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

Here it is given as

$y^{2}-7y+6=-6$

Adding 6 on both the side we get

$y^{2}-7y+6+6=-6+6$

$y^{2}-7y+12=0$

Which is Quadratic Equation in STANDARD form Where,

$a=1\\b=-7\\c=12$

Therefore,

$y^{2}-7y+12=0$       ....Standard form.

$a=1\\b=-7\\c=12$    ......Numerical Coefficients.