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sergeinik [125]
3 years ago
8

QUESTION 1

Mathematics
1 answer:
Alexeev081 [22]3 years ago
6 0

Answer:

1. 9

2. 10

Step-by-step explanation:

idk if those first 2 are right

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Aaron answered 7 out of 12 questions correctly on his last English quiz. Find his grade
givi [52]
Divide 7 by 12
which would give you 0.58
so that’s 58%
7 0
3 years ago
Read 2 more answers
7(2x-5)-11=3(5x-2)-2x
ICE Princess25 [194]

Answer:

x=40

Step-by-step explanation:

7(2x-5)-11=3(5x-2)-2x      Distribute

14x-35-11=15x-6-2x          Simplify

14x-46=13x-6                   subtract 13x and add 46

x=40

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A shop owner offered a 20%discount off the regular price of a mirror.The amount of the discount is $3.00
Scrat [10]

Answer:

A) $15

Step-by-step explanation:

let x represent the regular price of the mirror

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8 0
3 years ago
Read 2 more answers
What’s the greatest mad
Nana76 [90]

Answer: Jason's team.

Step-by-step explanation: When finding the MAD, you need to find the mean of the data, which they said is 10.  The next step is to subtract numbers from the data from the mean, which is 10 for all three dot plots. For example, for Jason's team, we need to subtract all the 7's, 8's, 11's, 12's, and 13's, because those are the only parts of the plot with data.  Let's try subtracting 7 - 10.  The answer is -3, but we need to make it positive, because that's how data works, so it's actually 3.  You keep doing this for all three plots, which is provided below:

Jason's Team: 3, 3, 2, 2, 2, 1, 2, 3, 3, 3.

Hannah's Team: 3, 2, 2, 1, 0, 0, 1, 1, 3, 3.

Dion's Team: 1, 1, 1, 1, 0, 0, 0, 0, 1, 3.

Now, the next step is adding all these values and dividing it by ten, since that's how many numbers there are for the data.

Jason's Team MAD: 2.4.

Hannah's Team MAD: 1.6.

Dion's Team MAD: 0.8

As you can see, Jason's Team has the greatest MAD, which is your answer.

Let me know if this is right! :)

8 0
2 years ago
Hi!!!<br>Calcula los divisores de cada número :<br>8, 12 ,24 , 25 , 28, <br>please . _ .​
Kamila [148]
I think that it’s 23
6 0
3 years ago
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