Answer:
1. Angle ABC = Angle DEF
2. Angle BCA = Angle EFD
3. Segment AC = Segment DF
4. Segment BA = Segment ED
The center-radius form of the circle equationis in the format (x – h)2<span> + (y – k)</span>2<span> = r</span>2<span>, with the center being at the point (h, k) and the radius being "r". Therefore the radius of the circle with the given equation would be </span>√9 or 3, first option. Hope this answers the question.
Answer:
Step-by-step explanation:
2
,
−
150
∘
)
=
(
2
,
210
∘
+
n
⋅
360
∘
)
=
(
2
,
4
π
3
+
n
⋅
2
π
)
,
n
∈
Z
as polar forms
(
2
,
150
∘
)
in polar
=
(
−
√
3
,
−
1
)
in Cartesian form
2
,
−
150
∘
)
=
(
2
,
210
∘
+
n
⋅
360
∘
)
=
(
2
,
4
π
3
+
n
⋅
2
π
)
,
n
∈
Z
as polar forms
(
2
,
150
∘
)
in polar
=
(
−
√
3
,
−
1
)
in Cartesian form
