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Natasha_Volkova [10]
3 years ago
13

Which inequality represents this sentence?

Mathematics
2 answers:
Vladimir [108]3 years ago
6 0
Yes it is correct because c and d are wrong, so if you look at a it is greater than the other problem which is wrong so the answer is b. 6+2<9+3 hope this  helped.
olga_2 [115]3 years ago
5 0
6 + 2 < 9 + 3...u r correct
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Square root of 5u+2 = square root of 3u+14
alina1380 [7]
Sqrt(5u + 2) = sqrt(3u + 14)
Square both sides to clear the square root.
5u + 2 = 3u + 14
subtract 3u from both siides
2u + 2 = 14
subtract 2 from both sides
2u = 12
divide both sides by 2
u = 6
When you square a square root you MUST check the solution.
sqrt(5*6 + 2) = sqrt(3*6 + 14)
sqrt(32) = sqrt(32)

8 0
3 years ago
You roll a fair 6-sided die what is p (not 3)
Ulleksa [173]
As a fraction, the exact answer is 5/6
In decimal form, the approximate answer is 0.8333

To get this answer, note how there are 5 ways to roll something that isn't a three (1,2,4,5,6) out of 6 ways total (1,2,3,4,5,6)

So you simply divide the two values to get 5/6 = 0.8333
8 0
3 years ago
Read 2 more answers
Matthew invested $3,000 into two accounts. One account paid 3% interest and the other paid 8% interest. He earned 4% interest on
boyakko [2]

<u>Answer:</u>

<em>Mathew invested</em><em> $600 and $2400</em><em> in each account.</em>

<u>Solution:</u>

From question, the total amount invested by Mathew is $3000. Let p = $3000.

Mathew has invested the total amount $3000 in two accounts. Let us consider the amount invested in first account as ‘P’

So, the amount invested in second account = 3000 – P

Step 1:

Given that Mathew has paid 3% interest in first account .Let us calculate the simple interest (I_1) earned in first account for one year,

\text {simple interest}=\frac{\text {pnr}}{100}

Where  

p = amount invested in first account

n = number of years  

r = rate of interest

hence, by using above equation we get (I_1) as,  

I_{1}=\frac{P \times 1 \times 3}{100} ----- eqn 1

Step 2:

Mathew has paid 8% interest in second account. Let us calculate the simple interest (I_2) earned in second account,

I_{2} = \frac{(3000-P) \times 1 \times 8}{100} \text { ------ eqn } 2

Step 3:

Mathew has earned 4% interest on total investment of $3000. Let us calculate the total simple interest (I)

I = \frac{3000 \times 1 \times 4}{100} ----- eqn 3

Step 4:

Total simple interest = simple interest on first account + simple interest on second account.

Hence we get,

I = I_1+ I_2 ---- eqn 4

By substituting eqn 1 , 2, 3 in eqn 4

\frac{3000 \times 1 \times 4}{100} = \frac{P \times 1 \times 3}{100} + \frac{(3000-P) \times 1 \times 8}{100}

\frac{12000}{100} = \frac{3 P}{100} + \frac{(24000-8 P)}{100}

12000=3P + 24000 - 8P

5P = 12000

P = 2400

Thus, the value of the variable ‘P’ is 2400  

Hence, the amount invested in first account = p = 2400

The amount invested in second account = 3000 – p = 3000 – 2400 = 600  

Hence, Mathew invested $600 and $2400 in each account.

3 0
3 years ago
Read 2 more answers
Help please! Identify an equation in point slope form for the line perpendicular to Y =-4x + 8 that passes through (-2, 7)
777dan777 [17]

Answer:

D. y-7=\frac{1}{4}(x+2)

Step-by-step explanation:

The point-slope form of a line is given by:

y-y_1=m(x-x_1)

The line given to us has equation; y=-4x+8.

The slope of this line is -4. The of the line perpendicular to this line is the negative reciprocal of the slope of the given line.

Our slope of interest is therefore; m=\frac{1}{4}

Since the point goes through (-2,7), we have x_1=-2,y_1=7.

We plug in the slope and the point into the point-slope formula to obain;

y-7=\frac{1}{4}(x--2)

The required equation is:

y-7=\frac{1}{4}(x+2)

3 0
3 years ago
Marla has $95.50 in her savings account. She deposits $5 every week. Her mother also deposits $20 into the account every time Ma
tiny-mole [99]
Coefficient: 20 or 5
Variable:  c or w
Constant:  95.50

Pt B:  20(5) + 5(20) + 95.50
          100 + 100 + 95.50
          295.50

Pt C:The coefficient of c would change to 10
8 0
3 years ago
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