Question

The equation of the line passing through the points (−10, 0) and (−8, 20) can be expressed as y = mx + b. Give the value of b.

Answer 1

(-10, 0) and (-8,20)

y=mx+b

here m is slope and b is y intercept

firstly we have to find the value of m , that is slope

formula is

$m=\frac{(y_{2} - y_{1})}{(x_{2}- x_{1})}$

So $m=\frac{20-0}{-8-(-10)}= \frac{20}{2}=10$

Plug in the function\

$y=10 x+b$

Now plug any one point in the function to find the value of b

$0= 10 (-10) +b$

$0=-100+b$

Add 100 to both sides

b=100

Answer 2

20-0/-8+10= 20/2= 10

y-0=10(x+10)

y=10+100

b=100