<em>The answer is: your GPS unit cannot send signals to the satellite when it cannot reach it by line of sight.
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<em>GPS signals are based on frequencies that can be blocked by solid objects (like walls and roofs). A GPS device is using a series of satellites to detect and see where it is physically located. These frequencies are sent from these plates (satellites) and we cannot expect it to go through all kinds of barriers. When you use a GPS inside a building, a wide variety of physical barriers and potential interference sources make it difficult for the device to detect your location accurately.
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<span>Not a valid IPv6 address
A valid IPv6 address consist of 8 groups of 4 hexadecimal numbers separated by colons ":". But that can make for a rather long address of 39 characters. So you're allowed to abbreviate an IPv6 address by getting rid of superfluous zeros. The superfluous zeros are leading zeros in each group of 4 digits, but you have to leave at least one digit in each group. The final elimination of 1 or more groups of all zeros is to use a double colon "::" to replace one or more groups of all zeros. But you can only do that once. Otherwise, it results in an ambiguous IP address. For the example of 2001:1d5::30a::1, there are two such omissions, meaning that the address can be any of
2001:1d5:0:30a:0:0:0:1
2001:1d5:0:0:30a:0:0:1
2001:1d5:0:0:0:30a:0:1
And since you can't determine which it is, it's not a valid IP address.</span>
Answer:
Check the explanation
Explanation:
A) Whenever C is sending to D, what other communications are possible?
C’s packet will be seen by A, B and D, but not by E. Thus, D can send to E at the sametime..
B) Whenever B is sending to A, what other communications are likely?
Even though B’s packet will not be seen by D, other nodes, e.g., E, or C, can’t send to D since the packets from these nodes will interfere with the packets from B at A. Therefore, other communications is not likely at the same time.
C) Whenever B is sending to C, what other communications are possible?
B’s packet will be seen by E, A and C, by not by D. therefore, E can send to D at the same point.
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mark me brainliestt :))
Answer:
BEGIN
SET count = 1
WHILE count <= 12 THEN
INPUT length
perimeter = length * length
PRINT perimeter
END WHILE
END
Explanation:
You can also set count to 0 and in while loop use count < 12 to loop just 12 times just as above
