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Andre45 [30]
3 years ago
5

jakes map shows the distance from the bake star cafe to the resturant supply store as 3cm. if the scale of the map is 1cm to 8 k

ilometers, what is the real distance from the shop to the store
Mathematics
2 answers:
alisha [4.7K]3 years ago
7 0

Answer:

the real distance from the shop to the store is 24\ Km

Step-by-step explanation:

we know that

The scale of the map is 1\ cm to 8\ km

so

by proportion

find the real distance for a distance in a map of  3\ cm

\frac{8}{1}\frac{Km}{cm}=\frac{x}{3}\frac{Km}{cm} \\ \\x=8*3\\ \\x=24\ Km

therefore

the real distance from the shop to the store is 24\ Km

SSSSS [86.1K]3 years ago
4 0
You would do 8*3 because it is the kilometers per centimeter times the centimeter map distance--
The answer is 24.

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4 years ago
Malcom coasted 32 miles from moon ridge to me tone and then pedaled back hard. If the round trip took 4 hours, what was malcoms
AURORKA [14]

Answer:

Malcom's average speed was 16 miles/hour.

Step-by-step explanation:

Given:

Distance from moon ridge to me tone = 32 miles.

Now including returned back journey.

So we can say that.

Total distance traveled = 32+32 =64\ miles

Also Given:

Time taken to travel total distance = 4 hours.

We need to find the average speed in miles per hour.

Solution:

Now we know that;

average speed is equal to Total distance traveled divided by Total time taken to travel the total distance.

framing in equation form we get;

average speed = \frac{64}{4}=16 \ mi/hr

Hence Malcom's average speed was 16 miles/hour.

3 0
4 years ago
Trigonometry
schepotkina [342]

The area of the triangle ABC is 207.5 square units.

Explanation:

The measurements of the sides of the triangle are AB=19, AC=24 and m\angle A=65^{\circ}

We need to determine the area of the triangle ABC.

<u>Area of the triangle:</u>

The area of the triangle can be determined using the formula,

{Area}=\frac{1}{2} b c \sin A

where b=19, c=24 and m\angle A=65^{\circ}

Substituting these values in the above formula, we get,

{Area}=\frac{1}{2}(19)(24)  \sin 65^{\circ}

Simplifying the values, we get,

{Area}=\frac{1}{2}(456) (0.91)

{Area}=\frac{1}{2}(414.96)

{Area}=207.48

Rounding off to the nearest tenth, we get,

{Area}=207.5

Thus, the area of the triangle ABC is 207.5 square units.

5 0
3 years ago
Read 2 more answers
The center of a circle is located at (3, 8), and the circle has a radius that is 5 units long. What is the general form of the e
n200080 [17]
Center of the circle: C=(3,8)=(h,k)→h=3, k=8
Radius of the circle: r=5
Standard form of the equation for the circle:
(x-h)^2+(y-k)^2=r^2
(x-3)^2+(y-8)^2=5^2
(x-3)^2+(y-8)^2=25

General for of the equation for the circle:
(x)^2-2(x)(3)+(3)^2+(y)^2-2(y)(8)+(8)^2=25
x^2-6x+9+y^2-16y+64=25
x^2+y^2-6x-16y+73=25
x^2+y^2-6x-16y+73-25=25-25
x^2+y^2-6x-16y+48=0

Answer: The general form of the equation for the circle is:
x^2+y^2-6x-16y+48=0
4 0
4 years ago
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