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satela [25.4K]
4 years ago
9

The center of a circle is located at (3, 8), and the circle has a radius that is 5 units long. What is the general form of the e

quation for the circle?
Mathematics
1 answer:
n200080 [17]4 years ago
4 0
Center of the circle: C=(3,8)=(h,k)→h=3, k=8
Radius of the circle: r=5
Standard form of the equation for the circle:
(x-h)^2+(y-k)^2=r^2
(x-3)^2+(y-8)^2=5^2
(x-3)^2+(y-8)^2=25

General for of the equation for the circle:
(x)^2-2(x)(3)+(3)^2+(y)^2-2(y)(8)+(8)^2=25
x^2-6x+9+y^2-16y+64=25
x^2+y^2-6x-16y+73=25
x^2+y^2-6x-16y+73-25=25-25
x^2+y^2-6x-16y+48=0

Answer: The general form of the equation for the circle is:
x^2+y^2-6x-16y+48=0
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