Number 2 is the correct answer
Answer:
Try another browser
Explanation:
Some browsers do not support advanced features like flex box.
Answer:
Document properties
Explanation:
From the list of given options, document properties answers the question.
Every computer file has its details which include (but not limited to) the file name, file type, file permission, date etc.
The above details and many more are makes it easy to identify files.
To get a document property, right click on the file/document, select properties, then select the details tab.
On the details tab, you will see a comprehensive list of the properties attributed to that particular documents
Answer:
Option (a)
Explanation:
It is true that managers takes some interviews and some tests which include questions which are able to identify the capabilities of the employee. Their field of expertise can be known by these tests which helps in which project they should put under where their skills will bloom and they can be more efficient. It helps manager to know if the employee is the best fit for their company or not.
Answer:
The Solution Code is written in Java.
- public class Main {
- public static void main(String[] args) {
- System.out.print("Please enter an integer: ");
- Scanner input = new Scanner(System.in);
- int number = input.nextInt();
- System.out.print("Prime numbers less than or equal to " + number + " : ");
- for(int i=2; i <= number; i++){
- if(checkPrime(i)){
- System.out.print(i + " ");
- }
- }
- }
- public static Boolean checkPrime(int num){
- for(int i=2; i < num; i++)
- {
- if(num % i == 0){
- return false;
- }
- }
- return true;
- }
- }
Explanation:
Firstly, we create a function to check if a number is prime (Line 18 - 27).
- This function will take one input value which is an integer, num.
- To check if the input num is a prime, we can use modulus operator, %, to confirm if the num is divisible by any number starting from 2 to num - 1 (Line 19 - 24).
- If the num is divisible by any number expect 1 and itself, it should equal to zero and return false to indicate it is not a prime number.
- If all the num (except 1 and itself) is not divisible, the function will return true (Line 25).
Next, in our main program part (Line 3 - 16)
- Prompt the user to input a number (Line 5 - 7)
- Using a for-loop, we can keep calling the checkPrime() function by passing a current number (starting from 2 to input number) as argument (Line 12). The checkPrime() function will run and return true it the current number is prime, return false if it is not prime.
- If the checkPrime() function return true, it will print the current number before proceed to the iteration of the for-loop to repeat the same check prime procedure (Line 13)
- At the end all the prime numbers less than or equal to the input number will be printed out in the terminal
