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3 years ago

A DFA is equivalent in power to an NFA. True False

Computers and Technology

1 answer:

sattari [20]3 years ago

4 0

Answer: True

Explanation:

Yes, the given statement is true that a DFA is equivalent to NFA in terms of power. For any type of NFA we can easily build an equal DFA so, the NFA are not much powerful as compared to DFA. Both NFA and DFA are characterized by a similar type of class.

DFA is a special case of NFA and They both defined in the same class of language. Each condition in the DFA get summarized by all the condition that the NFA has itself.

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I believe that the answer is D.
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Given a sorted list of integers, output the middle integer. A negative number indicates the end of the input (the negative numbe

masya89 [10]

Answer:

The program in Python is as follows:

myList = []

num = int(input())

count = 0

while num>=0:

myList.append(num)

count+=1

num = int(input())

myList.sort()

mid = int((count-1)/2)

print(myList[mid])

Explanation:

This initializes the list

myList = []

This gets the first input

num = int(input())

This initializes count to 0

count = 0

The following is repeated until the user inputs a negative number

while num>=0:

This appends the input number to the list

myList.append(num)

This increments count by 1

count+=1

This gets another input

num = int(input())

This sorts the list

myList.sort()

Assume the number of inputs is odd, the middle element is calculated as

mid = int((count-1)/2)

This prints the middle element

print(myList[mid])

From the complete question. the condition that ends the loop is a negative integer input

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3 years ago

) Perform error checking for the data point entries. If any of the following errors occurs, output the appropriate error message

emmainna [20.7K]

Answer:

In Python:

entry = input("Sentence: ")

while True:

if entry.count(",") == 0:

print("Error: No comma in string")

entry = input("Sentence: ")

elif entry.count(",") > 1:

print("Error: Too many comma in input")

entry = input("Sentence: ")

else:

ind = entry.index(',')+1

if entry[ind].isnumeric() == False:

print("Comma not followed by an integer")

entry = input("Sentence: ")

else:

break

print("Valid Input")

Explanation:

This prompts the user for a sentence

entry = input("Sentence: ")

The following loop is repeated until the user enters a valid entry

while True:

This is executed if the number of commas is 0

if entry.count(",") == 0:

print("Error: No comma in string")

entry = input("Sentence: ")

This is executed if the number of commas is more than 1

elif entry.count(",") > 1:

print("Error: Too many comma in input")

entry = input("Sentence: ")

This is executed if the number of commas is 1

else:

This calculates the next index after the comma

ind = entry.index(',')+1

This checks if the character after the comma is a number

if entry[ind].isnumeric() == False:

If it is not a number, the print statement is executed

print("Comma not followed by an integer")

entry = input("Sentence: ")

If otherwise, the loop is exited

else:

break

This prints valid input, when the user enters a valid string

print("Valid Input")

Note that: entry = input("Sentence: ") is used to get input

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