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3 years ago

Triangle A'B'C' is a reflection of triangle ABC across the line I. Select ALL

Mathematics

1 answer:

Inessa05 [86]3 years ago

8 0

Answer:

Step-by-step explanation:

x- axis is 2 units away

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In65 - lnX = 39<br> What does X=?

Hunter-Best [27]

Answer:

<h2>The answer is 7.47</h2>

Step-by-step explanation:

In this problem we are going find the natural logarithmic of the numbers involved and solve for x

$ln65-Ln x= 39\\$

from tables

$4.17-ln x= 39\4.17-39= lnx\\-34.83=lnx\\$

taking the exponents of both sides we have

$e^-^3^4^.^8^3= x\\x= 7.47$

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3 years ago

each of the letters in the word SAMSUNG are on separate cards, face down on the table. If you pick a card at random, what is the

shutvik [7]

There are 7 cards. The number of possible correct picks is 2 (if you pick an 'S') plus 1 (if you pick the 'U') = 3 ways to succeed. So the probability of success is 3/7 ... about 43% .

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3 years ago

Suppose that the area between a pair of concentric circles is 49pi. Find the length of a chord in the larger circle that is tang

Lapatulllka [165]

Answer:

14 units

Step-by-step explanation:

We are given that the area between two concentric circles is $49\pi$

We have to find the length of chord in the larger circle that is tangent to the smaller circle.

Let $r_1,r_2$ be the radius of two circles.

$r_1$ be the radius of small circle and $r_2$ be the radius of large circle

We know that area pf circle= $\pi r^2$

Area of large circle = $\pi r^2_2$

Area of small circle = $\pi r^2_1$

Area between two circles = $49\pi$

Area of large circle -Area of small circle= $49\pi$

$\pi r^2_2-\pi r^2_1=49\pi$

$\pi(r^2_2-r^2_1)=49$

By pythagorus theorem

$AD^2=OA^2-OD^2$

$AD^2=r^2_2-r^2_1$

$AD=49$

$AD=\sqrt{49}=7$

Length of chord= $2\cdot AD$

Hence, the length of chord of the larger circle = $2\cdot7=14$ units

7 0

3 years ago

Read 2 more answers

What is 30 divided by 6

choli [55]

Answer:

The answer is 5

Step-by-step explanation:

6÷30=5

6×5=30

7 0

3 years ago

Read 2 more answers

Point T is at (-2, 5). What are the<br> coordinates of point T'after<br> Ry-axis Rx-axis?

OLga [1]

Answer:

(5,-2)

Step-by-step explanation:

Here, we want to find the coordinates of point after reflection on both x and y axes

After reflection given that the line is y = x

The new points become (y,x)

And as such in this case, we have (5,-2)

3 0

3 years ago