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3 years ago

Negative 12 over negative 6, I forgot what to do

2 answers:

7 0

Negative 12 over negative 6.

Over means to divide (fraction).

-12/-6

A negative divided by a negative equals a positive.

-12/-6 = 2

Answer: 2

Airida [17]3 years ago

4 0

Negative 12 over negative 6
= -12 / (-6)
= 12/6 (a negative number divided by a negative number is a positive number)
= 2

The final answer is 2~

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3 years ago

Simplify. 2 x (3-1) + 3 07 8 O 10 O 11

myrzilka [38]

Answer:

Step-by-step explanation:

2 x (3-1) + 3

Evaluate using PEMDAS

Parenthesis

Exponents

Math and Division ( left to right )

Addition and Subtraction ( left to right )

2 x (3-1) + 3

According to PEMDAS we do the operations inside of the parenthesis first

3 - 1 = 2

We now have: 2 x 2 + 3

Next we do exponents

There are no exponents so let's move on to multiplication and division

There is indeed multiplication so we do it

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3 years ago

Solve the equation using the quadratic formula. Enter each solution in simplest form.

sergeinik [125]

For this case we have the following quadratic equation:

$x ^ 2-4x + 23 = 0$

The solutions will be given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Where:

$a = 1\\b = -4\\c = 23$

Substituting the values we have:

$x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (23)}} {2 (1)}\\x = \frac {4 \pm \sqrt {16-92}} {2}\\x = \frac {4 \pm \sqrt {-76}} {2}\\x = \frac {4 \pm \sqrt {76i ^ 2}} {2}\\x = \frac {4 \pmi \sqrt {76}} {2}\\x = \frac {4 \pmi \sqrt {2 ^ 2 * 19}} {2}\\x = \frac {4 \pm2i \sqrt {19}} {2}\\x = 2 \pm i\sqrt {19}$

We have two roots:

$x_ {1} = 2-i \sqrt {19}\\x_ {2} = 2 + i \sqrt {19}$

ANswer:

$x_ {1} = 2-i\sqrt {19}\\x_ {2} = 2 + i\sqrt {19}$

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4 years ago