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solong [7]
4 years ago
9

using the continuously compounding formula what would the balance be if you invest $5500 at a rate of 8% compunded continuously

for 6 years please show all your work.
Mathematics
2 answers:
fomenos4 years ago
5 0
\bf \qquad \textit{Continuous Compounding Amount}\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$5500\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
t=years\to &6
\end{cases}
\\\\\\
A=5500\cdot e^{0.08\cdot 6}
vodomira [7]4 years ago
4 0
The formula is A = Pe^(rt)
where A = amount in the account after a specified period of time
P = principle
e = a constant value (similar to using pi in a formula)
r = rate (change to a decimal)
t = time (in years unless otherwise specified)

A = 5500e^(.08*6)
A = $8888.41
Always round money to two decimal places unless told otherwise.
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3 0
3 years ago
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lyudmila [28]

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now, we know that y(5) = -23, which is another way of saying that when x = 5, y = -23, but we already knew that, we can get that by simply plugging it into the equation hmmm y'(5), well

\left. \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x} \right|_{\stackrel{x=5~}{\textit{\tiny y=-23}}}\implies \cfrac{-8(5)-4-(-23)}{5}\implies \cfrac{-21}{5}

8 0
3 years ago
Four different stores have the same digital camera on sale. The original price and discounts offered by each store are
inysia [295]

Answer:

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3 0
3 years ago
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Using your knowledge of exponential and logarithmic functions and properties, what is the intensity of a fire alarm that has a s
Ierofanga [76]

Option B:

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Solution:

Given sound level = 120 decibel

To find the intensity of a fire alarm:

$\beta=10\log\left(\frac{I}{I_0} \right)

where I_0=1\times10^{-12}\ \text {watts}/ \text m^2}

Step 1: First divide the decibel level by 10.

120 ÷ 10 = 12

Step 2: Use that value in the exponent of the ratio with base 10.

10^{12}

Step 3: Use that power of twelve to find the intensity in Watts per square meter.

$10^{12}=\left(\frac{I}{I_0} \right)

$10^{12}=\left(\frac{I}{1\times10^{-12}\ \text {watts}/ \text m^2} \right)

Now, do the cross multiplication,

I=10^{12}\times1\times\ 10^{-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{12-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{0} \ \text {watts}/ \text m^2}

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Option B is the correct answer.

Hence I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}.

5 0
4 years ago
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dolphi86 [110]

The answer is that s = 55/42.

Here's how to solve it

3 0
3 years ago
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