Answer:
Step-by-step explanation:
According to the table, function g(x) reaches the max height of 33, approx.
The equation of motion is f(x) = -16x^2 + 42x + 12. We need to determine the maximum of this function. To do this, find the x-coordinate of the vertex, which is x = -b/(2a), or x = -42/(2*-16), or 1.31 sec.
Evaluating f(x) = -16x^2 + 42x + 12 at x = 1.31 sec, we get f(1.31) = 39.6.
So it appears that f(x) has a higher max than does g(x); the difference is approx. 39.6 - 33, or 6.6
I honestly don't know because i'm only in sixth grade but I think that it might be 30*.
Answer:
0.078125.
Step-by-step explanation:
This is a geometric sequence with first term a1 = 20 and common ratio r = 10/20 = 5/10 = 0.5.
nth term = a1 r^(n -1) so here:
9th term = 20(0.5)^(9-1)
= 20(0.5)^8
= 0.078125.
Answer:
m=-2
Step-by-step explanation:
As the product of the roots of a quadratic equation is c/a in ax^2+bx+c=0
here a=2, b=+8, c=-m^3
Given c/a=4
-m^3/2=4
-m^3=8
m^3= -8
m=-2.
