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Roman55 [17]
3 years ago
10

Evaluate 1 3 m − 1 − 1 2 n 3 1 ​ m−1− 2 1 ​ nstart fraction, 1, divided by, 3, end fraction, m, minus, 1, minus, start fraction,

1, divided by, 2, end fraction, n when m = 2 1 m=21m, equals, 21 and n = 1 2 n=12n, equals, 12.
Mathematics
1 answer:
luda_lava [24]3 years ago
3 0

Answer:

  0

Step-by-step explanation:

Apparently, you want the value of ...

  \dfrac{1}{3}m-1-\dfrac{1}{2}n = \dfrac{m}{3}-\dfrac{n}{2}-1\\\\=\dfrac{21}{3}-\dfrac{12}{2}-1=7-6-1\\\\=\boxed{0}

The value of the given expression for the given variable values is zero.

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Using binomial theorem, expand (x+6)^8 <br><br> edit: You could use the help of combinations too.
Pavlova-9 [17]

x⁸ + 48x⁷ + 1008x⁶ + 12096x⁵ + 90720x⁴ + 435456x³ + 1306368x² + 2239488x + 1679616

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We know

(x+y)ⁿ = ∑ ⁿCₐxⁿ⁻ᵃyᵃ

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So,

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         = ₓ⁸ + 8x⁷ₓ 6 + 28x⁶ₓ 36 + 56x⁵ₓ 216 + 70x⁴ₓ 1296 + 56x³ₓ 7776 + 28x²ₓ     46656 + 8x . 279936 + 1679616

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Thus, the expansion of ( x+6)⁸ using binomial theorm is

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6 hours because
double- 3 hours
triple- 6 hours
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