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Marina CMI [18]
3 years ago
11

What is the explicit rule that describes the arithmetic sequence shown in the graph

Mathematics
1 answer:
boyakko [2]3 years ago
5 0

Answer:

an = 50 + (n - 1)150

Step-by-step explanation:

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How to solve to system y=x^2-2 y=2x+1
vovikov84 [41]

Answer:

the solutions are (3, 7) and (-1, -1)

Step-by-step explanation:

Insert the " = " symbol between the two equations, obtaining:

y = x^2 - 2 = y = 2x + 1

Then x^2 - 2 = 2x + 1, or

x^2 - 2x - 3 = 0, and this can be factored into (x - 3)(x + 1) = 0.

Thus, the x values that satisfy this system are {-1, 3}.

Use y = 2x + 1 to find the corresponding y values:

y = 2(-1) + 1 = -1

and

y = 2(3) + 1 = 7

Then the solutions are (3, 7) and (-1, -1)

7 0
3 years ago
B
Tom [10]

Answer:

(a) 320 cm²

(b) 75 cm³

Step-by-step explanation:

The scale factor from A to B is 8/4 = 2.

The scale factor of the areas is 2² = 4.

The scale factor of the volumes is 2³ = 8.

(a)

80 cm² * 4 = 320 cm²

(b)

600 cm / 8 = 75 cm³

8 0
3 years ago
I need help fast 17 points please help​
Alisiya [41]

Answer:

C f-1 (x) = x- 2

Step-by-step explanation:

The inverse is usually shown by putting a little "-1" after the function name, and reversing the units.

6 0
3 years ago
Need help, it's interest rate!
navik [9.2K]

Answer:

B is your answer to this question.

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
A pool measuring 18 meters by 22 meters is surrounded by a path of uniform width. If the area of the pool and the path combined
suter [353]

Answer: the width of the uniform path is 9 meters.

Step-by-step explanation:

Let x represent the width of the uniform path.

A pool measuring 18 meters by 22 meters is surrounded by a path of uniform width. It means that the combined length of the pool and the uniform path is (18 + 2x) meters and the combined width of the pool and the uniform path is (22 + 2x) meters.

If the area of the pool and the path combined is 1440 square meters, it means that

(18 + 2x)(22 + 2x) = 1440

396 + 36x + 44x + 4x² = 1440

4x² + 80x + 396 - 1440 = 0

4x² + 80x - 1044 = 0

Dividing both sides of the equation by 4, it becomes

x² + 20x - 261 = 0

x² + 29x - 9x - 261 = 0

x(x + 29) - 9(x + 29) = 0

x - 9 = 0 or x + 29 = 0

x = 9 or x = 29

Since the width cannot be negative, then x = 9 meters

5 0
3 years ago
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