X^2 - 6x + 9 = -1 + 9. We need to solve for x.
First, add one on each side of the equation:
x^2 - 6x + 9 + 1 = -1 + 9 + 1
x^2 - 6x + 10 = 9
Then subtract 9 from each side:
x^2 - 6x + 10 - 9 = 9-9
x^2 - 6x + 1 = 0
Now we got an equation = 0. This an equation from the second degree, it represented by a parabola which turns up since a>0.
This equation is the developed form as ax^2 + bx + c with a=1; b = -6; and c=1.
Now, to find the zeroes of this equation, we need to find delta Δ.
Δ = b^2 - 4ac.
If Δ>0, the equation admits 2 zeroes: x=(-b-√Δ)/2a and x = (-b+√Δ)/2a.
If Δ<0, the equation doesn't admits any zero.
If Δ=0, the equation admits one zero x = -b/2a
Δ = (-6)^2 - 4(1)(1)
Δ = 36 - 4
Δ = 32
Δ>0
So the zeroes of the equation are:
x = (-b-√Δ)/2a = (6-4√2)/2
x = (-b+√Δ)/2a = (6+4√2)/2
Hope this Helps! :)
<span><span>1.
If we get an odd number first (probability 5/10 = 1/2), then the only way to get a number greater than 9 is the 10 (probability 1/9, since only 9 papers remain). This gives 1/2 * 1/9 = 1/18.</span></span><span><span>
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</span></span><span><span>2.
We would expect that P(2 white cards) = P(1 white card)*P(2nd white card given 1 white card).</span></span><span><span /></span><span><span>This gives the equation 14/95 = 2/5 * x<span>
</span></span></span><span><span><span>Solving for x gives x = 7/19.</span></span></span><span><span>
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</span></span><span><span>3. There are a total of 4 favorable results: 1, 4, 5, 6. Out of the 6 possibilities, this is a probability of 4/6 = 2/3.</span></span>
Answer:
The correct answer is 1,3, and 6
7/8 x 1/4 =
7/32
7/32 would be the simplest form, unless they want a decimal.
Both pentagons have the same number of sides:)
