This one is best done by elimination:
We need to start 4 meters away, so B is clearly wrong.
We first move towards Mr. Wilson (i.e. distance is decreasing) so A is wrong.
Our speed is faster on the way back, so the two sloped section must have differing slopes, so D is wrong.
(D also doesn't start at 4, it's wrong for two reasons.)
Only C is left.
We can check each part to make sure. First we start at 4m, then move away, then stay still (zero slope) for three seconds, then move back faster (higher slope). All parts check out ok.
Since the triangles are the same, just flipped that means that all angles and segments are the same as well
I'm not sure if that's the "correct" way to prove it but that's why they're equal
Answer:
C. m∠4 = m∠8
D. m∠2 = m∠7
Step-by-step explanation:
Here, we use the principles of alternate angles, corresponding angles and vertically opposite angles to confirm which of the statements are true. Alternate angles are always equal, corresponding angles are equal, likewise vertically opposite angles.
From the given question, it was given that a is parallel to b. Thus, it can be observed and deduced that;
m∠4 = m∠8 (corresponding angles)
and
m∠2 = m∠3 (vertically opposite angles)
m∠3 = m∠7 (corresponding angles)
So that,
m∠2 = m∠7
Thus in the question, statements C and D are true.
Idk if this is correct but y+g>5 or 5<y+g
