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Katarina [22]
4 years ago
15

Can a right triangle have a leg that is 10 meters long and a hypotenuse that is 10 meters long

Mathematics
2 answers:
pishuonlain [190]4 years ago
5 0
Lets see
a and b are legs
c=hypotnuse
a^2+b^2=c^2
10^2+b^2=10^2
100+b^2=100
minus 100 both sides
b^2=0
b=0
false, if you have a leg legnth 0, then they lines are right on top of each other




no cannot
bogdanovich [222]4 years ago
3 0
Solutions

To solve this problem we have to use the Pythagorean theorem. You can only use the Pythagorean theorem in Right Triangles. The longest side of the triangle is called the "hypotenuse". C² is the longest side so it is the hypotenuse . To calculate c² we have to do α² + β² = c². 

<span>Given 

</span>α² = 10 
c² = 10 

Solve 

α² + β² = c² 
α² (10²) + β² = c² (10²) 
100 + β² = 100 
β² = 100 - 100 = 0 

Simplify 

<span>A right triangle can not have a leg that is 10 meters long and a hypotenuse that is 10 meters long. </span>
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Answer:

x = 10.2

Step-by-step explanation:

To find x, use Cosine

Cosine = \frac{adjacent}{hypothenuse}

⇒ Cosine 22 = \frac{x}{11}

Cosine of 22 is 0.93

⇒ 0.93 =  \frac{x}{11}

Multiply 11 on both sides:

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Round to the nearest tenth:

10.23 ⇒ 10.2

x = 10.2

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Answer:

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5 0
4 years ago
For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 8 N acts on
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4 0
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Read 2 more answers
Solve the solution using the substitution method <br><br>3x +5y = 29<br>y= -4x -1
Artist 52 [7]
3x + 5y = 29         first equation
y = -4x - 1             second equation

substitute the second equation to the first equation;
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solve for x;
-17x - 5 = 29
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so;
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hope this helps, God bless!
3 0
3 years ago
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