Question

Assume that when adults with smartphones are randomly​ selected, 57​% use them in meetings or classes. If 9 adult smartphone users are randomly​ selected, find the probability that at least 3 of them use their smartphones in meetings or classes The probability is ?

Answer 1

Answer: 0.9617

Step-by-step explanation:

Given : The proportion of adults use their phones in meetings or classes : p=0.57

Number of adults randomly selected : n= 9

Let x be the random variable that represents the number of adults use their phones in meetings or classes.

By using binomial probability formula, to find the probability of getting success in x trials.

$P(x)=^nC_xp^x(1-p)^{n-x}$

The probability that at least 3 of them use their smartphones in meetings or classes will be :-

$P(x\geq3)=1-P(x$

Hence, the required probability is 0.9617 .