All categories

4 years ago

Which equation represents a line that is parallel to 2x-3y=9

1 answer:

4 0

Two lines are parallel if they have the same slope but a different y intercept. A line with the same slope and y int as another one will be the exact same
Slope in standard form is -a/b, so your slope is 2/3 and your y int is -3
For example:
y=2/3x+1

You might be interested in

A jelly bean has seven calories. How many calories in six beans?

Kitty [74]

Answer:

Step-by-step explanation:

Because if 1 jelly bean has 7 calories how many in 6 beans well you multiply

3 0

3 years ago

Given the following vector field and oriented curve C, evaluate ModifyingBelow Integral from nothing to nothing With Upper C Bo

sladkih [1.3K]

Answer:

The value of the line integral is $\frac{157}{2}$ .

Step-by-step explanation:

Given a path C, with parametrization r(t) for $t_0\leq t \leq t_1$ , we have that

$\int_{C}F dr = \int_{t_0}^{t_1} F(r(t)) \cdot r'(t) dt$ where $\cdot$ is the dot product between two vectors.

In our case, we have $r(t) = (6t,11t^2), 0\leq t\leq 1$ . Then $r'(t) = (6,22t)$ . In this case we have that F(x,y) = (x,y). Then, $F(r(t)) = (6t, 11t^2)$

$\int_{C}F dr = \int_{0}^{1} (6t,11t^2)\cdot(6,22t) dt = \int_{0}^{1} 36t+11\cdot 22 t^3= \left.(36\frac{t^2}{2}+11\cdot 22 \frac{t^4}{4})\right|_{0}^{1} = \frac{36}{2}+\frac{11\cdot 22}{4}= \frac{157}{2}$

4 0

4 years ago

HELP ASAP

Gnom [1K]

Answer:

(-1--2)/(4-2) = 1/2

y+1 = (1/2)(x-4) from plugging in (4,-1) but you could have used either point

2y+2 = x-4

2y = x-6

4 0

3 years ago

A bookshelf is about 9.3*10^-2 meters thick. A bookshelf is about 1.865*10^1 meters long. About how many copies of this book wil

Ksenya-84 [330]

For this case, the first thing we must do is define variables.

We have then:

x: length of the bookshelf

y: thickness of each book

The equation for the number of books is:

$N = \frac{x}{y}$

Substituting values we have:

$N = \frac{1.865 * 10 ^ 1}{9.3*10^{-2}}$

Doing the calculation we have:

$N = 200$

Answer:

200 copies of this book will fit on the bookshelf

3 0

3 years ago

Suppose that X has a Poisson distribution with a mean of 64. Approximate the following probabilities. Round the answers to 4 dec

o-na [289]

Answer:

(a) The probability of the event (X > 84) is 0.007.

(b) The probability of the event (X < 64) is 0.483.

Step-by-step explanation:

The random variable X follows a Poisson distribution with parameter λ = 64.

The probability mass function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, ...$

(a)

Compute the probability of the event (X > 84) as follows:

P (X > 84) = 1 - P (X ≤ 84)

$=1-\sum _{x=0}^{x=84}\frac{e^{-64}(64)^{x}}{x!}\\=1-[e^{-64}\sum _{x=0}^{x=84}\frac{(64)^{x}}{x!}]\\=1-[e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{84}}{84!}]]\\=1-0.99308\\=0.00692\\\approx0.007$

Thus, the probability of the event (X > 84) is 0.007.

(b)

Compute the probability of the event (X < 64) as follows:

P (X < 64) = P (X = 0) + P (X = 1) + P (X = 2) + ... + P (X = 63)

$=\sum _{x=0}^{x=63}\frac{e^{-64}(64)^{x}}{x!}\\=e^{-64}\sum _{x=0}^{x=63}\frac{(64)^{x}}{x!}\\=e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{63}}{63!}]\\=0.48338\\\approx0.483$

Thus, the probability of the event (X < 64) is 0.483.

5 0

3 years ago