1) marbles altogether = 3+4=7
P(black) = 3/7
2) P(first black marble)= 3/7
second black marble - When you removed 1st one only 2 black marbles are left and altogether marbles that are left = 6
P(second black marble) = 2/6=1/3
P(2 black marbles without replacement) means black and black marbles without replacement.
P(2 black marbles without replacement) =3/7*1/3=1/7
3) P(first black marble)= 3/7
When you put that black marble back, you got again <span>3 black marbles and 4 red marbles in a bag. So,
</span> P(second black marble)= 3/7
P(2 black marbles with replacement)=3/7*3/7= 9/49<span>
</span>
1. 9b
2.x^5
3.(3y)/12
4.(1-k)+7
Answer:
Photo 1: (a) C
(b) A
(c) D
Photo 2: 12.0416cm
Photo 3: 15.5242cm
Step-by-step explanation:
Photo 1: (a) 6×4=24
(b) 6(5)+6=36
(c) 6×6=36
Photo 2: Using Pythagoras' Theorem,
Unknown side length= square root symbol [(8×8)+(9×9)]
= 12.0416cm (6sf)
Photo 3: Using Pythagoras' Theorem,
AC= square root symbol (AB^2+BC^2)
=square root symbol [(15×15)+(4×4)]
= 15.5242cm (6sf)
A=4 4 times 12 is 48 minus 24 is 24
