1. You have the following quadratic equation and to solve it, you must follow the steps below:
<span>
x</span>²<span>+3=9x
2. The form of the equation that you need to apply the quadratic formula, is:
ax</span>²+bx+c=0
<span>
3. Then:
</span>
x²<span>+3=9x
</span> x²-9x<span>+3=0
</span><span>
4. The quadratic formula is shown below:
x=(-b±√(b^2-4ac))/2a
5. Then, you have:
a=1
b=-9
c=3
6. When you substitute the values into the quadratic formula, you obtain:
x1=0.34
x2=8.65</span>
Answer:
Step-by-step explanation:
x = first number, y = second number
4x - 3y = 12
2x + 3y = 6
------------------add
6x = 18
x = 18/6
x = 3
4x - 3y = 12
4(3) - 3y = 12
12 - 3y = 12
-3y = 12 - 12
-3y = 0
y = 0
solution : (3,0)
Answer:
let no.be x
its half= x/2
its one third= x/3
its one sixth=x/6
atq.....avg of x= x/2+x/3+x/6//3=6x/6//3=x/3
now...x/3+6=x...as the no.is 6 more than its avg
x= 9
It's the parallelogram. Therefore
ML = JK, JM = KL, m∠L = m∠J, m∠M = m∠K and m∠M + m∠L = 180°.
ML = 21 → JK = 21
JM = 29 → KL = 29
m∠L = 127° → m∠J = 127°
m∠M + m∠L = 180° → m∠M + 127° = 180° → m∠M = 53°
m∠M = 53° → m∠K = 53°
