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emmasim [6.3K]
3 years ago
6

100% of will give me 93

Mathematics
1 answer:
Art [367]3 years ago
5 0

Answer:

Hi Wdym m=by 100% of will give me 93

Step-by-step explanation:

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Factorise fully 18x+9
galina1969 [7]

Answer: 9 (2x + 1)

Step-by-step explanation: i hope i helped

5 0
3 years ago
Perpendicular lines do not intersect. True or false?
saul85 [17]

Answer:

Perpendicular lines are lines that intersect at a right (90 degrees) angle

Step-by-step explanation:

4 0
3 years ago
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What is the quotient of (x3 + 6x2 + 11x + 6) ÷ (x2 + 4x + 3)? x + 2 x – 2 x + 10 x + 6
evablogger [386]

Answer:

x + 2

Step-by-step explanation:

If we know one of the factors, we should be able to use long division.

We can divide the trinomial by the binomial and find the other factor.

                 <u>x  +  2</u><u>                   </u>

x² + 4x + 3)x³ + 6x² + 11x + 6

                  <u>x³ + 4x² + 3x</u>

                         2x² + 8x + 6

                         <u>2x² + 8x + 6</u>

                                           0

Thus,

\dfrac{x^{3} + 6x^2 + 11x + 6} {x^{2} + 4x + 3} = \mathbf{x + 2}

6 0
3 years ago
PLEASE HELP ANSWER FAST I WILL GIVE BRAINLIEST!!!!!
bija089 [108]

Answer:

Take the number of weeks as x

12x = 544 - 100

x =444/12

x = 37

Thus it would take her 37 weeks to buy her a laptop

6 0
3 years ago
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1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by
Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0
3 years ago
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