Time out = d/so = d/523
time back = d/sb = d/415
t = time out + time back
11 = d/523 + d/415 find common deneminator
11 = (415d + 523d)/(523*415)
11*523*415 = 415d + 523d
2387495 = 938d
d = 2545 miles
hope this help
Answer:
Yes
Step-by-step explanation:
The angles are identical, so they are congruent.
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Answer:
Stratified Random sampling
Step-by-step explanation:
When a random observations are selected from a number of individual groups in a particular population, the type of sampling technique is called Stratified Random sampling. Stratified Random sampling begins with the partitioning or splitting or a population into subgroups. A number of random selection are then made from each of the subgroups to form a collection of larger samples. This is different from the simple random sampling technique which makes random selection directly from a larger sample or population without prior partitioning of the population. The different grades of students represents the individual stratum from which random selections are made.
For every 9 kids 5 are girls
there are 3 sets of 9
so 5 x 3 = 15
there are 15 girls
Answer:
Comparing each pair of lines,
AB and EF,
BC and FG,
CD and GH,
DA and HE.
For, AB and EF,
If we take a look at both the lines they are the mirror image of each other, the distance between point A and B is 1 unit upwards, and 2 unit sidewise, similarly between point E and F the distance is 1 unit upwards, and 2 unit sidewise. therefore, the length of both the lines is the same.
Also, we can use the formula, for the distance between two points on a coordinate plane,
,
As we can see in the image,
A = (-1, 1),
B = (-3, 2),
C = (-4, 4),
D = (-2, 6),
E = (2, 0),
F = (4, 1),
G = (5, 3),
H = (3, 5),
Solving using the formula,
AB = EF = √5,
BC = FG = √5,
CD = GH = √8,
DA = HE = √26,
Therefore, the length of all the sides of the polygon are the same,
Hence, the two figures are congruent.
Step-by-step explanation:
