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2 years ago

5

Given the function f(x)=-8x2+8x+9,state whether the vertex represents a maximum or minimum point for the function.

1 answer:

Lelechka [254]2 years ago

5 0

8x2+8x+9
=16x+8x+9
=24x+9
Are that right

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Find the equation of the line given the slope and the y-intercept

GREYUIT [131]

Answer:

y = $\frac{1}{2}x + 3$

Step-by-step explanation:

The equation for a linear graph is usually written in the following format...

y = mx + b

Where m would be the slope, usually referring to rise over run and b would be the y-intercept (where the line crosses the y-axis). From the graph, we can see that the line crosses the y-axis at point 3 so b would be 3. The graph also shows us that for every 1 value that the line rises it moves to the right 2 values. Therefore, the slope would be 1/2. Using these values we can create the following equation...

y = $\frac{1}{2}x + 3$

7 0

2 years ago

P = 3. Q = -2. Solve 4PQ

gtnhenbr [62]

4(3)(-2)
=12(-2)
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6 0

2 years ago

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What is the slope of the line whose equation is 2x+3y = -12?

luda_lava [24]

Answer:

slope = - $\frac{2}{3}$

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

2x + 3y = - 12 ( subtract 2x from both sides )

3y = - 2x - 12 ( divide all terms by 3 )

y = - $\frac{2}{3}$ x - 4 ← in slope- intercept form

with slope m = - $\frac{2}{3}$

6 0

2 years ago

i need help asap please dont type random anwsers, that will result in it being deleted. GIVING BRAINLIEST ONLY TO CORRECT, INCOR

Veseljchak [2.6K]

Answer:

The area of the rectangle <em>TOUR</em> is 80.00 unit².

Step-by-step explanation:

The area of a rectangle is computed using the formula:

$Area\ of\ a\ Rectangle=length\times width$

Since the dimensions of the rectangle are not provided we can compute the dimensions using the distance formula for two points.

The distance formula using the two point is:

$distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Considering the rectangle <em>TOUR</em> the area formula will be:

Area of Rectangle <em>TOUR</em> = <em>TO × OU</em>

The co-ordinates of the four vertices of a triangle are:

T = (-8, 0), O = (4, 4), U = (6, -2) and R = (-6, -6)

Compute the distance between the vertices <em>T</em> and <em>O</em> as:

$TO=\sqrt{(4-(-8))^{2}+(4-0)^{2}}\\=\sqrt{12^{2}+4^{2}} \\=\sqrt{160} \\=4\sqrt{10}$

Compute the distance between the vertices <em>O </em>and <em>U</em> as:

$OU=\sqrt{(6-4)^{2}+(-2-4)^{2}}\\=\sqrt{2^{2}+6^{2}} \\=\sqrt{40} \\=2\sqrt{10}$

Compute the area of rectangle TOUR as follows:

$Area\ of\ TOUR=TO\times OU\\=4\sqrt{10}\times 2\sqrt{10}\\=80\\\approx80.00 unit^{2}$

Thus, the area of the rectangle <em>TOUR</em> is 80.00 unit².

6 0

2 years ago

Write a decimal that is less than 6.73

faust18 [17]

4.2 would be an example, but there are many more. Honestly, it wouldn't matter as long as it was less than 6.73.

3 0

2 years ago

Read 2 more answers