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Alla [95]
3 years ago
12

How can you determine if a relation represents as an equation is a function?

Mathematics
1 answer:
elixir [45]3 years ago
7 0
It is relatively easy to determine whether an equation is a function by solving for y. When you are given an equation and a specific value for x, there should only be one corresponding y-value for that x-value. For example, y = x + 1 is a function because y will always be one greater than x.
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-4x plus 3 equals -11
Hoochie [10]
-4x+3= -11
      -3   -3
-4x= -14
___  ___
-4x    -4x

= 3.5
3 0
3 years ago
Do diagonals of a rhombus bisect the vertex angles???
katrin [286]

Answer:

Yes, one of a rhombus's properties is that the diagonals bisect vertex angles.


7 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Korvikt [17]

Answer:

Plot the following points on the graph

(-1, \frac{1}{2}), (0, 1), (1, 2), (2, 4), (3, 8)

Step-by-step explanation:

If the equation for the line is y = 2^{x}, whatever the power/exponent  "x" equals, then y is equal to however many times 2 is multiplied by x.

For example, if our domain is {-1, 0, 1 , 2, 3}

then we would plug in each x value into the exponent to find the y-value in order to plot the points to solve the problem.

If x = -1, then y = 1/2. **If there is an a negative exponent it would get turned into a positive fraction with the denominator as the positive version of that number.

y = 2^{-1}  = \frac{1}{2^{1} } = \frac{1}{2}

If x = 0, then y = 1

**When the exponent is 0, the number automatically equals 1.

If x = 1, then y = 2.

If x = 2, then y = 4

If x = 3, then y = 8

So you would plot the following coordinates on the graph:

(-1, \frac{1}{2})

(0, 1)

(1, 2)

(2, 4)

(3, 8)

7 0
3 years ago
The function y=2.5x+3 can be used to determine the cost in dollars for a taxi ride of x miles. What is the rate of change of the
notsponge [240]

Answer:

C. $2.50

Step-by-step explanation:

x=1 y=5.5

x=2 y=2.5

8 0
3 years ago
A rectangle has a length of x inches and a width 2 inches less than the length.If the dimensions were doubled, what would be the
zheka24 [161]

If the dimensions of the rectangle were doubled, the area in square inches is: Area = 4x^2 - 8x

  • Let the length of the rectangle be L.
  • Let the width of the rectangle be W.

<u>Given the following data:</u>

  • Length = x inches
  • Width = x - 2 inches

If the dimensions of the rectangle were doubled, the value of L and W becomes;

L = 2x

W = 2(x - 2)

Mathematically, the area of a rectangle is given by the formula;

Area = Length × Width

Area = 2x × 2(x-2)

Area = 2x × 2x - 4

Area = 4x^2 - 8x  square inches.

Find more information: brainly.com/question/897975

3 0
3 years ago
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