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TEA [102]
3 years ago
14

In ΔWXY, w = 8.1 inches, x = 2.9 inches and y=5.5 inches. Find the measure of ∠Y to the nearest 10th of a degree.

Mathematics
1 answer:
Nostrana [21]3 years ago
3 0

Answer:

21.3

Step-by-step explanation:

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n the figure below, A, B, and C represent the areas of the squares with side lengths a, b, and c, respectively. If B = 441 squar
atroni [7]

Answer:

hello 765

Step-by-step explanation:

3 0
4 years ago
The graph of y = f(x) is shown. Choose all the true statements.
dexar [7]

Answer:

−2 is a member of the domain of f.

f(0) > 0

Step-by-step explanation:

Statement 1 is TRUE. Domain value includes set of values of x of the function. -2 is plotted on the x-axis on the graph. Therefore, it is a member of domain of f.

Statement 2 is incorrect. Range includes all possible y-values of the function. On the graph, no y-value plotted is -2. Therefore, -2 is NOT a member of the range of f.

Statement 3 is TRUE.

f(0) is approximately 2.2 on the graph. i.e. at x = 0, y ≈ 2.2.

Therefore, f(0) > 0.

Statement 4 is INCORRECT.

f(2) = 1, that is at x = 2, y = 1 as seen in the graph. Therefore, f(2) is not greater than 2.

8 0
4 years ago
HELP!!!!!!!
anygoal [31]

Answer:

Sample Response: First, the like terms had to be combined using the lowest common denominator (LCD). Then the subtraction property of equality was used to isolate the variable term. Finally, both sides of the equation were multiplied by the reciprocal of the coefficient to solve for a.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help! <br><br> 6.2 divided by (2x + 1)= 2 1/3 divided by 4
guajiro [1.7K]

Answer:

x=2/3

Step-by-step explanation:

(2x+1)/2 = 2 1/3/4

Multiply 4 on both sides:

2x+1=2 1/3

Rewrite:

2x+1=7/3

Subtract 1 on both sides:

2x=4/3

Divide 2 on both sides:

x=2/3

Thus x=2/3

Hope this helps!

7 0
3 years ago
Read 2 more answers
Suppose a tub has the shape of an elliptical paraboloid given by z = ax2+by2 (where a, b are some positive constants). If a marb
Umnica [9.8K]

Answer:

It would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

Step-by-step explanation:

It would roll to the direction of maximum decrease, which is the -1 times the direction of maximum increase, which is given by the gradient of the function.  

Since  

z =  ax^2  + by^2

For this case, the gradient of your function would be

\nabla z  = (2ax , 2by)

And  -1  times the gradient of your function would be

-\nabla z  = (-2ax , -2by)\\

Then, at

 (1,1,a+b),\\x = 1 \\y = 1

So it would go towards

v = (-2a,-2b)

The magnitud of that vector is

|v| =  2\sqrt{a^2+b^2}

and to conclude it would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

6 0
3 years ago
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