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agasfer [191]
3 years ago
14

In the reaction __H2 + O2 → 2H2O, what coefficient should be placed in front of H2 to balance the reaction?

Computers and Technology
2 answers:
malfutka [58]3 years ago
8 0
The answer is:  [B]:  " 2 " .
_____________________________________________
Explanation:
____________________________________
Given the chemical equation:
____________________________________

     <u> ? </u> H₂ + O₂ → 2 H₂<span>O   ;
____________________________________________
</span>      → <span> We are asked, "What coefficient, if any — should be put in front of the:  " H</span>₂ " ;
__________________________________________________
          (which is on the "left-hand side" side of the chemical equation given—      the "reactants") ;

     →  to get a balanced chemical equation?
__________________________________________________
 →  Let us examine the "right-hand side" of this chemical equation—the product(s).  In this case, the "product" given is:  " 2 H₂O " .  

So, on the "right hand side", we have:
__________________________________________________
     1)  4 "H's" → {Two "H₂" 's = 2 * 2 = "4 H's"} ;  <u><em>and</em></u>:
     2)  2 "O's" → { Two "O's").
__________________________________________________
   So, the left-hand side should have:
__________________________________________________
     1)  4 "H's" ;  <u><em>and</em></u>:
     2)  2 "O's" ;
__________________________________________________
Let us examine the left-hand side (the "reactants").
__________________________________________________
                  " <u> ? </u><u /> H₂  +  O₂ " ; 
__________________________________________________
On the left-hand side, we already have: 
__________________________________________________
     1)   " 2  O's " ;   →  one "O₂" = "2 O's" ;  and:
     2)    "2  H's " ;   →  one "H<span>₂" .</span>

Now, we would need:
__________________________________________________
A "<u>total of "4 H's</u>".  Is there any number we could put as a coefficient on the other reactant, which happens to be:  "H₂" ;  to make a <u><em>total of</em></u> "4 H's" ?          

         {Note: There are only these TWO (2) reactants in this chemical equation.}.  

        → The "H₂" ;  as it stands alone, is insufficient—since that would be only                                                                                         "2 H's".
 __________________________________________________
     →  Thus, we can rule out:  "Answer choices: [A] and [D]."  
___________________________________________________
<u>Note</u>:  
→  Choice [A]:  "1" ;  The coefficient, "1";  is generally not (never?) used; and basically would function as the same as:
          →  Choice: [D]:  "<span>no coefficient is needed".
</span>→  <span>Choices [A] & [D]: would leave us with only "2 H's" on the "reactants side" (i.e. "left-hand side of the equation"; and we need FOUR ("4 H's").
__________________________________________________
Since we are given:  "H</span>₂" ; what coefficient could we put in front of this to get:       "4 H's" ?  (4÷2 =2).  So we could put a "2" in front of the "H₂" ; to get: 
    "4 H's".  The coefficient, "2" , corresponds directly with: 
__________________________________________________
                                             → Answer choice:  [B]:  "2" .
_________________________________________________
   { <u>NOTE</u>:  The remaining answer choice, [C], which is, "3" ; is INCORRECT; since 3 "H₂'s" would be "6 H's" ; (since 3 * "2 H's" equal "6 H's") ; which is too many "H's" → We need <u>exactly</u> "4 H's".}.
_________________________________________________
   So, the correctly balanced equation is:

             2 H₂ + O₂ → 2 H₂O  ; 
_________________________________________________
     → The coefficient that goes before the "H₂" ; to make this chemical equation balanced, is:  "2" . 
_________________________________________________
The correct answer is:  [B]:  "2" .  

      → The coefficient that goes before the "H₂" is:  "2" .
_________________________________________________
         Hope this answer—and {lengthy} explanation—is of help!
_________________________________________________
zvonat [6]3 years ago
8 0

The answer is B (2).

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Shapes.java

public abstract class Shapes {

}

Triangle.java

public abstract class Triangle extends Shapes {

}

IsoscelesTriangle.java

public class IsoscelesTriangle extends Triangle {

double side1;

double side2;

public double getSide1() {

return side1;

}

public void setSide1(double side1) {

this.side1 = side1;

}

public double getSide2() {

return side2;

}

public void setSide2(double side2) {

this.side2 = side2;

}

public IsoscelesTriangle(double side1, double side2) {

super();

this.side1 = side1;

this.side2 = side2;

}

public double perimeter()

{

return 2*side1+side2;

}

public double area()

{

return side1*side2/2;

}

}

EquilateralTriangle.java

public class EquilateralTriangle extends Triangle {

double side;

public EquilateralTriangle(double side) {

super();

this.side = side;

}

public double getSide() {

return side;

}

public void setSide(double side) {

this.side = side;

}

public double perimeter()

{

return 3*side;

}

public double area()

{

return 1.73205*side*side/4;

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}

Quadrilateral.java

public abstract class Quadrilateral extends Shapes {

}

Rectangle.java

public class Rectangle extends Quadrilateral {

double length;

double breadth;

public double getLength() {

return length;

}

public void setLength(double length) {

this.length = length;

}

public double getBreadth() {

return breadth;

}

public void setBreadth(double breadth) {

this.breadth = breadth;

}

public Rectangle(double length, double breadth) {

super();

this.length = length;

this.breadth = breadth;

}

public double perimeter()

{

return 2*(length+breadth);

}

public double area()

{

return length*breadth;

}

}

Square.java

public class Square extends Quadrilateral {

double side;

public Square(double side) {

super();

this.side = side;

}

public double getSide() {

return side;

}

public void setSide(double side) {

this.side = side;

}

public double perimeter()

{

return 4*side;

}

public double area()

{

return side*side;

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}

Rhombus.java

public class Rhombus extends Quadrilateral {

double length;

double breadth;

public Rhombus(double length, double breadth) {

super();

this.length = length;

this.breadth = breadth;

}

public double getLength() {

return length;

}

public void setLength(double length) {

this.length = length;

}

public double getBreadth() {

return breadth;

}

public void setBreadth(double breadth) {

this.breadth = breadth;

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return 2*(length+breadth);

}

public double area()

{

return length*breadth/2;

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}

Test.java

import java.util.Scanner;

public class Test {

public static void main(String[] args) {

// TODO Auto-generated method stub

Scanner sc=new Scanner(System.in);

System.out.println("Enter your choice");

System.out.println("1. Create IsoscelesTriangle ");

System.out.println("2. Create EquilateralTriangle");

System.out.println("3. Create Rectangle");

System.out.println("4. Create Square");

System.out.println("5. Create Rhombus");

System.out.println("6. Create Circle");

int choice=sc.nextInt();

switch(choice)

{

case 1:

System.out.println("Enter two sides of triangle");

double side1=sc.nextDouble();

double side2=sc.nextDouble();

IsoscelesTriangle isosceles=new IsoscelesTriangle(side1, side2);

System.out.println("Area of the triangle is "+isosceles.area());

System.out.println("Perimeter of the triangle is "+ isosceles.perimeter());

break;

case 2:

System.out.println("Enter side of the triangle");

double side=sc.nextDouble();

EquilateralTriangle equilateralTriangle=new EquilateralTriangle(side);

System.out.println("Area of the triangle is "+equilateralTriangle.area());

System.out.println("Perimeter of the triangle is "+ equilateralTriangle.perimeter());

break;

case 3:

System.out.println("Enter length and breadth");

double length=sc.nextDouble();

double breadth=sc.nextDouble();

Rectangle rectangle =new Rectangle(length, breadth);

System.out.println("Area of rectangle is "+rectangle.area());

System.out.println("Perimeter of the rectangle is "+rectangle.perimeter());

break;

case 4:

System.out.println("Enter side of the square");

double squareside=sc.nextDouble();

Square square=new Square(squareside);

System.out.println("area of the square is "+square.area());

System.out.println("Perimeter of the square is "+square.perimeter());

break;

case 5:

System.out.println("Enter length and breadth of rhombus");

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double rbreadth=sc.nextDouble();

Rhombus rhombus=new Rhombus(rlength, rbreadth);

System.out.println("area of the rhombus is "+rhombus.area());

System.out.println("Perimeter of the rhombus is "+rhombus.perimeter());

break;

case 6:

System.out.println("Enter radius of circle");

double radius=sc.nextDouble();

Circle circle=new Circle(radius);

System.out.println("area of the circle is "+circle.area());

System.out.println("Perimeter of the circle is "+circle.perimeter());

break;

}

}

}

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