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Sedbober [7]
3 years ago
7

Simplify the expression

Mathematics
2 answers:
Marizza181 [45]3 years ago
8 0

Answer:

\frac{8x^{10}z}{y^{4}}

Step-by-step explanation:

The expression \frac{(2x^{3}z^{2})^{3}}{x^{3} y^{4}z^{2}.x^{-4}z^{3}}

Using laws of exponents

The law that

x^{m} x^{n} = x^{m+n}

Solving in the denominator

\frac{(2x^{3}z^{2})^{3}}{x^{3} y^{4}z^{2}.x^{-4}z^{3}}=\frac{(2x^{3}z^{2})^{3}}{x^{3-4} y^{4}z^{2+3}}=\frac{(2x^{3}z^{2})^{3}}{x^{-1} y^{4}z^{5}}

The law that

(x^{m})^{n} =x^{mn}

solving in the numerator

\frac{(2x^{3}z^{2})^{3}}{x^{-1} y^{4}z^{5}}=\frac{2x^{3.3}z^{2.3}}{x^{-1} y^{4}z^{5}}=\frac{2x^{9}z^{6}}{x^{-1} y^{4}z^{5}}

The law that

\frac{x^{m}}{x^{n}} = x^{m-n}

solving the fraction

\frac{2x^{9}z^{6}}{x^{-1} y^{4}z^{5}}=\frac{2x^{9-(-1)}z^{6-5}}{y^{4}}

Resulting

\frac{8x^{10}z}{y^{4} }

emmainna [20.7K]3 years ago
6 0

Answer:

sorry really blurry sorry too blurry I cannot really read it I'm sorry again

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(a)

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