Question

En la figura se muestran dos bloques de m1= 0,8 Kg y m2= 0,2 kg si el bloque de masa m2 es arrastrado por el bloque masa m1 calcular la aceleracion del sistema y la aceleracion de la cuerda

Answer 1

Answer:

The acceleration in the system and in the rope is same as 5.88 m/s2.

Step-by-step explanation:

The figure shows two blocks of m1 = 0.8 Kg and m2 = 0.2 kg if the block of mass m2 is dragged by the block of mass m1 calculate the acceleration of the system and the acceleration of the rope

Let the acceleration is a and the tension in the string is T.

Use Newton's second law

$m_1 g - T = m_1 a ..... (1)\\\\T -m_2 g = m_2 a ......(2)\\\\Add both of them \\\\(m_1 - m_2) g = (m_1 + m_2) a \\\\(0.8-0.2)\times9.8 = (0.8+0.2)a\\\\a = 5.88 m/s^2$