Question

The mean pulse rate​ (in beats per​ minute) of adult males is equal to 69 bpm. For a random sample of 166 adult​ males, the mean pulse rate is 68.6 bpm and the standard deviation is 10.6 bpm. Find the value of the test statistic.

Answer 1

Answer: $-0.4862$

Explanation:

Given : The mean pulse rate​ (in beats per​ minute) of adult males$\mu=69\text{ bpm}$

For sample : Size = $n=166$

Mean : $\overline{x}=68.6\text{ ppm}$

Standard deviation : $\sigma=10.6\text{ bpm}$

We assume that its a normal distribution , since the sample size is large (>30) then test applied here is z-test .

The formula to calculate the z-statistic is given by :-

$z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

$\Rightarrow\ z=\dfrac{68.6-69}{\dfrac{10.6}{\sqrt{166}}}=-0.486192404782\approx-0.4862$

Hence, the value of the test statistic = $-0.4862$