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lina2011 [118]
3 years ago
13

You invest $720 in an account that has an annual interest rate of 6.2%, compounded semiannually. How much money will be in the a

ccount after 5 years? Round your answer to the nearest whole number and include units.
Show all work.
Mathematics
1 answer:
Daniel [21]3 years ago
3 0
The appropriate formula is
  A = P(1 +r/n)^(nt)
where P is the amount invested (720)
  r is the annual interest rate (0.062)
  n is the number of compoundings per year (2)
  t is the number of years (5)

Filling in the given numbers, you have
  A = $720·(1 + .062/2)^(2·5)
  A = $720·1.031^10
  A ≈ $977

After 5 years the account will hold $977.
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If x+y= 15, y+z=25, and x+z=20, what is the arithmetic mean of x,y, and z
Mama L [17]
X + y = 15
Rearrange this to isolate for x.
x = 15 - y


x + z = 20
Rearrange this to isolate for x also.
x = 20 - z

Since they are both equal to x, that means they are equal to each other (x = x)

Set them equal to each other. 

15 - y = 20 - z
Now, isolate for y.

y = 15 - 20 + z

Now, use y + z = 25 and isolate for y.
y = 25 - z

Since they are both equal to y, we set them equal to each other.

15 - 20 + z = 25 - z
Solve for z
z + z = 25 - 15 + 20
2z = 30
2z/2 = 30/z
z = 15

Now you can plug the value for z into the other equations to find y and x.

x + z = 20
x +15 = 20
x = 20-15
x = 5

y + z = 25
y + 15 = 25
y = 25 - 15
y = 10

6 0
3 years ago
A. 7 ft<br><br> B. 8 ft<br><br> C. 49 ft<br><br> D. 576 ft
AleksAgata [21]
Your equation is gonna be a^2-24^2=25^2 and your answer is 7.
4 0
2 years ago
Read 2 more answers
The perimeter of a rectangular field is 100 feet. Which *COULD NOT* be the length and width of the perimeter?
Rina8888 [55]

Answer:

D) L=50 W=50

Step-by-step explanation:

Just "plug and chug" these numbers and see which doesn't work.

A is not it, 20+30=50 (then *2 because we need 4 sides not just 2) 50*2=100

B isn't it, 10+40=50*2=100

C ain't it either 49+1=50*2=100

D is the answer 50+50=100*2=200

7 0
3 years ago
A University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students. A s
Alla [95]

Answer:

The point estimate for this problem is 0.48.

Step-by-step explanation:

We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.

A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".

<em>Let </em>\hat p<em> = proportion of students who felt comfortable reporting cheating by their fellow students</em>

<u></u>

<u>Now,  point estimate (</u>\hat p<u>) is calculated as;</u>

                               \hat p=\frac{X}{n}

where, X = number of students who answered yes = 1,344

            n = number of students surveyed = 2,800

So, Point estimate (\hat p)  =  \frac{1,344}{2,800}

                                     =  <u>0.48 or 48%</u>

5 0
3 years ago
Can u guys help me with #1 plz guys now
myrzilka [38]
3

the area is 41.6cm which is 1foot  4 3/8 inches.

So 6in + 6in + 6in = 1ft 6in, which will be enough to cover the floor.
3 0
3 years ago
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