Point-slope form: y-y1 = m(x-x1)
Standard form: ax + by = c
Slope-intercept form: y = mx+b
Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.
To create point-slope form, we need to get one point from the graph. Let's use (3,0).
To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.
To get standard form, solve the equation in terms of C.
Point-slope form: y = -4/3(x-3)
Slope-intercept form: y = -4/3x + 4
Standard form: 4/3x + y = 4
Answer: $4.20
Step-by-step explanation:
Answer:
Step-by-step explanation:
what do u mean
The equations give you information as to where to plot points.
For y = -x + 1, you know the slope is -1, and the line intersects the y-axis at (0, 1). The y-axis is the vertical line; to plot (0, 1), find 1 on the vertical line and mark it. Now, the slope is -1; that means the line will slope downwards. To plot more points, count 1 unit down from (0, 1) and 1 unit to the right. You should end up at (1, 0).Connect those and you have a line.
For y = -2x + 4, the slope is -2 (so it will also slope downwards), and the y-intercept is 4. Find (0, 4) and plot it. The -2 tells you to count 2 units down (instead of 1 like we did for the last equation) and 1 over. That is the second line.
I hope this helps.
