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3 years ago

Consider the function f(x)=x^2-5. If g(x)=f(x-7), what can be said about g(x)? check all that apply

1 answer:

6 0

Sounds as tho' there were several answers to choose from. Please make sure to share them when you post your questions.

If f(x)=x^2-5, and g(x)=f(x-7), then g(x) = (x-7)^2-5 = x^2 - 14x + 49 - 5, or
g(x) = x^2 - 14x + 45 (answer)

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The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

8 0

3 years ago

Alona [7]

Similarities:
Have a consistent change for every interval can be represented as functions of a variable points lie on a line.

Differences: linear equations represent all solutions to all x values, whereas arithmetic sequences pick integer spacing

4 0

3 years ago

The cities Cleveland, Ohio; Erie, Pennsylvania; and Rochester, New York, in respective order, lie approximately in a straight li

Ann [662]

Answer:

Erie to Rochester is 145 miles

Step-by-step explanation:

If we designate the points of interest as C, E, and R, we are told that ...

CE + ER = CR . . . . . the various distances are segments of a straight line

For CE = 94 and CR = 239, we can fill in the given information and solve for ER.

94 + ER = 239

ER = 239 -94 . . . . . . subtract 94 from both sides of the equation

ER = 145

The distance from Erie to Rochester is 145 miles.

7 0

3 years ago

Please help!!

vodomira [7]

Answer:

The population will be 240,116

Step-by-step explanation:

Exponential growth can be represented by the expression:

$P(t) = P_i\,(1+r)^t$

where:

$P(t)$ is the population at time (t)

$P_i$ is the initial value of the population

"r" is the annual rate of growth (written in decimal form)

and "t" is the time in years.

Therefore in this situation, P(16) is what we want to find [the population after 16 years]

the initial population $P_i$ is 110,000

the rate of growth is 0.05 [decimal form of 5%]

and t is 16 years.

Replacing all these in the given functional form gives:

$P(t) = P_i\,(1+r)^t\\P(16)=110000\,(1+0.05)^16\\P(16)=240116$

4 0

3 years ago

A circular aluminum sign has a radius of 28 centimeters. If a sheet of aluminum costs $0.33 per square centimeter, how much will

pshichka [43]

Answer:

I'm not gonna answer

Step-by-step explanation:

but u have to multiply and divide your answer

4 0

3 years ago