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svetlana [45]
3 years ago
11

Consider the function f(x)=x^2-5. If g(x)=f(x-7), what can be said about g(x)? check all that apply

Mathematics
1 answer:
pochemuha3 years ago
6 0
Sounds as tho' there were several answers to choose from.  Please make sure to share them when you post your questions.

If  <span>f(x)=x^2-5, and g(x)=f(x-7), then g(x) = (x-7)^2-5 = x^2 - 14x + 49 - 5, or
g(x) = x^2 - 14x + 45 (answer)</span>
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PLEAsE HELP[<br> simplify:<br> (3x^4y^4)(5x^4) / 20xy^2
almond37 [142]

Answer:

\frac{3x^6y^2}{4}

Step-by-step explanation:

\frac{3x^6y^2}{4}

3 0
3 years ago
Find the midpoint of the segment with the given endpoints (5,-9) and (-2,-2)
QveST [7]
Another way to solve this is to use the Midpoint Formula.  The midpoint of a segment joining points (x_1,y_1) and (x_2,y_2) is

\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \right)

So the midpoint of your segment is

\left(\frac{5+(-2)}{2},\frac{-9+(-2)}{2}\right) = \left(\frac{3}{2},-\frac{11}{2} \right)

Perhaps it helps to see that the x-coordinate of the midpoint is just the average of the x-coordinates of the points.  Ditto for the y-coordinate of the midpoint; just average the y's.
6 0
3 years ago
3/4 x 1/2 <br> Help need it plss ;-;
Shkiper50 [21]

Answer:

3/8

Step-by-step explanation:

3/4 divide 2 = 4÷2= 3/8

4 0
2 years ago
Read 2 more answers
What is .825252525 repeating as a fraction
masya89 [10]
Let d = 0.825252525..., then
10d = 8.25252525...=8\frac{25}{10^2-1}=8\frac{25}{99}

Therefore,
d=\frac{8}{10}+\frac{25}{990}=\frac{8(99)+25}{990}=\frac{817}{990}
5 0
3 years ago
Consider he function f(x)=2x-4 a.find the inverse of (x) and name it g(x) . Show your work &lt;br /&gt;&lt;br /&gt; B. Use funct
inna [77]

A.\\f(x)=2x-4\to y=2x-4\\\\\text{change x to y and y to x}\\\\x=2y-4\\\\\text{solve for y}\\\\2y-4=x\qquad|+4\\\\2y=x+4\qquad|:2\\\\y=\dfrac{1}{2}x+2\\\\f^{-1}(x)=g(x)=\dfrac{1}{2}x+2\\B.\\\text{Verifying if two functions are inverses of each other is a simple two-step process.}\\1.\ \text{Plug}\ f(x)\ \text{into}\ g(x)\ \text{and simplify}\\2.\  \text{Plug}\ g(x)\ \text{into}\ f(x)\ \text{and simplify}\\\\If\ g[f(x)]=f[g(x)]=x,\ then\ functions\ are\ inverses\ of\ each\ other.

f(x)=2x-4,\ g(x)=\dfrac{1}{2}x+2\\\\g[f(x)]=\dfrac{1}{2}(2x-4)+2=\dfrac{1}{2}(2x)+\dfrac{1}{2}(-4)+2=x-2+2=x\\\\f[g(x)]=2\left(\dfrac{1}{2}x+2\right)-4=2\left(\dfrac{1}{2}x\right)+2(2)-4=x+4-4=x\\\\\text{Since the results above came out OK, both}\ x,\text{ then we can claim}\\\text{that functions f (x) and g (x) are inverses of each other.}

6 0
3 years ago
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