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creativ13 [48]
3 years ago
5

What is the quotient??

Mathematics
1 answer:
Elena L [17]3 years ago
7 0

I think it's 5'9

HOPE IT HELPS!!! :)

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A box contains 9 identical glass spheres that are used to make snow globes.
DIA [1.3K]
Uhmmm B I pretty sure
5 0
3 years ago
I will give brainliest
Natasha_Volkova [10]

Answer:

  • 225°
  • quadrant 3
  • reference angle of 45°

Step-by-step explanation:

585-360= 225

225° is in quad 3

reference angle for quad 3 is

225° - 180°

3 0
3 years ago
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Your welcome lolololololol


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3 years ago
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The graph of a line passes through the points (0, -2) and (6.0). What is
9966 [12]

Answer:

y=\frac{1}{3}x-2

Step-by-step explanation:

The equation of a line is given in the form  y=mx+b

Where

m is the slope with formula  m=\frac{y_2-y_1}{x_2-x_1}

and

b is the y-intercept [y axis cutting point of line]

Given the two points (0, -2) and (6,0),

x_1 = 0

y_1 = -2

x_2 = 6

y_2 = 0

Now, we find m using formula:

m=\frac{0+2}{6-0}=\frac{1}{3}

Now we have

y=\frac{1}{3}x+b

Finding b, we plug in any (x,y) point. Lets put (6,0) and find b:

y=\frac{1}{3}x+b\\0=\frac{1}{3}(6)+b\\0=2+b\\b=-2

Thus,

equation of line = y=\frac{1}{3}x-2

5 0
3 years ago
How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy
Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

n \cdot (n+1) < 40000

Now we solve this inequation to the highest value of n that satisfy the inequation:

n^{2}+n < 40000

n^{2}+n -40000

The Quadratic Formula shows that roots are:

n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}

n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}

n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}

n_{1} \approx 199.501

n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}

n_{2} \approx -200.501

Only the first root is valid source to determine the highest possible value of n, which is n_{max} = 199. Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

6 0
3 years ago
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