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Amiraneli [1.4K]
3 years ago
15

What rule matches the function graphed below? Please help! Thanks!

Mathematics
1 answer:
True [87]3 years ago
6 0
Take any two points to find the slope of a line.  The slope will be equal to:

(y2-y1)/(x2-x1) and any two points will do...

I'll use (-2,4) and (0,0) :P so the slope is:

(0-4)/(0--2)=-4/2=-2, now we know the slope is -2 so:

y=-2x+b  (now we know b=0, but I'll use another point anyway to solve for b)

Let's use (-2,4) again...

4=-2(-2)+b

4=4+b

b=0

So the line is:

y=-2x
hope this helped!
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Solve the equation for x: c a−x/x−a =5x Answer: , a ≠ − 1/5
meriva

Answer:

\large\boxed{x=-\dfrac{1}{5}}

Step-by-step explanation:

\dfrac{a-x}{x-a}=5x\\\\\dfrac{(a-x)}{-(a-x)}=5x\qquad\text{cancel}\ (a-x)\\\\-1=5x\qquad\text{divide both sides by 5}\\\\-\dfrac{1}{5}=\dfrac{5x}{5}\to\boxed{x=-\dfrac{1}{5}}

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Answer:

72°

Step-by-step explanation:

180-3x=2x

5x=180

x=36

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Step-by-step explanation:

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Please I need it asap
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Answer:

5) √(3² + 5²) = √34

6) √(4² - 3²) = √7

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Step-by-step explanation:

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Look at the image. (calculus)
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<h3>Answer: Choice H)  2</h3>

=============================================

Explanation:

Recall that the pythagorean trig identity is \sin^2 x + \cos^2x = 1

If we were to isolate sine, then,

\sin^2 x + \cos^2x = 1\\\\\sin^2 x = 1-\cos^2x\\\\\sin x = \sqrt{1-\cos^2x}\\\\

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.

Through similar calculations, \cos x = \sqrt{1-\sin^2x}\\\\

Cosine is also positive in this quadrant.

-------------

So,

\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}\\\\\frac{\sin x}{\sin x}+\frac{\cos x}{\cos x}\\\\1+1\\\\2

Therefore,

\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}=2

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